22 Jan Shift 1 Paper Solution & Review – JEE Main | neetjeerankers.com

22 January Shift 1 – JEE Main Paper Solution & Review

🔵 PHYSICS (Questions + Options + Answer)
Q1. A projectile is thrown upward at an angle 60° with the horizontal. The speed of the projectile is 20 m/s when its direction of motion is 45° with the horizontal. The initial speed of the particle is, (1) 40√2 (2) 40 (3) 20√2 (4) 20√3
Ans: (3)
Q2. Match the following LIST–I (a) Spring constant (b) Thermal conductivity (c) Boltzmann constant (d) Inductance LIST–II (i) ML²T⁻²K⁻¹ (ii) ML⁻¹T⁻³K⁻¹ (iii) ML²T⁻²A⁻² (iv) MLT⁻² (1) a→ii, b→iv, c→i, d→iii (2) a→iv, b→iii, c→ii, d→i (3) a→iii, b→ii, c→iv, d→i (4) a→i, b→ii, c→iii, d→iv
Ans: (1)
Q3. The escape velocity from a spherical planet A is 10 m/s. The escape velocity from another planet B whose density and radius are 10% of planet A is ____ m/s.
Ans: 0.32 m/s
Q4. Two disc having same moment of inertia about their axis. Thickness is t₁ & t₂ and they have same densities. If R₁/R₂ = 1/R then find t₁/t₂.
Ans: 16
Q5. Two solid spheres masses 5 kg and 10 kg with radius 10 cm and 20 cm respectively are in contact as shown. Find the moment of inertia of the system about common tangent.
Ans: 0.63 kg-m²
Q6. A simple pendulum has a bob with mass m and charge q. The pendulum string has negligible mass. When a uniform horizontal electric field E is applied, the tension in the string changes. The final tension in the string, when pendulum attains equilibrium is
Ans: T = √[(mg)² + (qE)²]
Q7. The minimum frequency of photon required to break a particle of mass 15.348 amu into 4α-particle is ______.
Ans: 1.5 × 10²³ Hz
Q8. 7.9 MeV α-particle scatters from a target material of atomic number 79. Estimate the distance of closest approach.
Ans: 2.88 × 10⁻¹⁴ m
Q9. In series R–L circuit voltage of battery is 10 V. Resistance and inductance are 10 Ω and 10 mH respectively. Find the energy stored in inductor when current reaches 1/e times of maximum value. (1) 0.67 mJ (2) 1.33 mJ (3) 0.33 mJ (4) 0.50 mJ
Ans: (1)
Q10. Electric field in a region is given by E = Axi + Byj, where A = 10 V/m², B = 5 V/m². If the electric potential at a point (10, 20) is 500 V, then the electric potential at origin is (in V). (1) 2000 (2) 1000 (3) 500 (4) 0
Ans: (1)
Q11. During an adiabatic expansion the volume increases to 8 times and temperature reduces to 1/4th. What is the adiabatic constant for the gas?
Ans: 5/3
🟢 CHEMISTRY (Questions + Options + Answer)
Q1. Find the energy to excite electron from first Bohr orbit of hydrogen atom to 2nd Bohr’s orbit. (in eV)
Ans: 10.2 eV
Q2. Arrange the given metal ions in increasing order of number of unpaired electrons in low spin complex formed by Mn³⁺, Cr³⁺, Fe³⁺, Co³⁺. (1) Co³⁺ < Fe³⁺ < Mn³⁺ < Cr³⁺ (2) Co³⁺ < Mn³⁺ < Fe³⁺ < Cr³⁺ (3) Cr³⁺ < Mn³⁺ < Fe³⁺ < Co³⁺ (4) Cr³⁺ < Mn³⁺ < Co³⁺ < Fe³⁺
Ans: (1)
Q3. The order of electrophilic substitution when CHCl₃ and Methanol is added. (1) I⁻ < F⁻ < C₆H₅O⁻ < C₂H₅O⁻ (2) I⁻ > F⁻ > C₆H₅O⁻ > C₂H₅O⁻ (3) I⁻ > F⁻ > C₂H₅O⁻ > C₆H₅O⁻ (4) F⁻ < I⁻ < C₆H₅O⁻ < C₂H₅O⁻
Ans: (4)
Q4. K₂Cr₂O₇ is heated with KCl in presence of conc. H₂SO₄. Find the correct match of product with their oxidation state. (1) CrO₂Cl₂, +6 (2) Cr₂O₂Cl₂, +6 (3) Cr₂O₂Cl₂, +5 (4) CrO₂Cl₂, +5
Ans: (1)
Q5. Match the following Column-I with Column-II. Column-I (a) [Ag(NH₃)₂]⁺ (b) Zn–Hg/HCl (c) NH₂–NH₂/KOH (d) Cu²⁺/OH⁻ Column-II (i) Fehling’s solution (ii) Clemmenson’s reduction (iii) Tollen’s reagent (iv) Wolff-Kishner reduction (1) a(i), b(ii), c(iii), d(iv) (2) a(iv), b(iii), c(ii), d(i) (3) a(iii), b(ii), c(iv), d(i) (4) a(i), b(iii), c(iv), d(ii)
Ans: (3)
Q6. Given below are two statements. Statement I: HX bond length is higher in HCl than HF. Statement II: The lowest boiling point in hydride of group 15 element is having covalency 4. (1) Both statement-I and statement-II are correct (2) Both statement-I and statement-II are incorrect (3) Statement-I is correct and statement-II is incorrect (4) Statement-I is incorrect and statement-II is correct
Ans: (3)
Q7. When X and Y react with fluorine then it forms XF₃. The XF₃ is a Lewis acid and YF₃ is a Lewis base. Then hybridization of XF₃ and YF₃ is: (1) both sp² (2) both sp³ (3) sp² and sp³ (4) sp³ and sp²
Ans: (3)
Q8. Reactivity of following on the basis of SN1 mechanism. (1) IV > III > I > II (2) II > IV > III > I (3) III > IV > I > II (4) IV > III > II > I
Ans: (1)
Q9. A compound ‘A’ with molecular formula C₉H₁₁NO reacts with Br₂/NaOH to give (X). (X) on reaction with NaNO₂ in dil. HCl gives compound (Y). When (Y) is treated with CuCN, followed by hydrolysis gives (Z). The compound (A) on hydrolysis also gives compound (Z). Identify compound (A). (1) Option-1 (2) Option-2 (3) Option-3 (4) Option-4
Ans: (3)
Q10. Which of the following statement is correct regarding the nature and directive influence of –NO₂ group in nitration of benzene. (1) It is an activating group and ortho/para director (2) It is a deactivating group and ortho/para director (3) It is a deactivating group and meta director (4) It is an activating group and meta director
Ans: (3)
🔴 MATHEMATICS (Questions + Options + Answer)
Q1. \frac{\cos^2 48^\circ - \sin^2 12^\circ}{\sin^2 24^\circ - \sin^2 6^\circ} = \frac{\alpha + \beta\sqrt{5}}{2}
Ans: 4
Q2. Random variable x has the probability distribution x : 0 1 2 3 4 5 6 7 P(x): 0, 2k, k, 3k, 2k², 2k, k²+k, 7k² Then P(3 < x < 6) is equal to (1) 0.22 (2) 0.64 (3) 0.34 (4) 0.33
Ans: (1)
Q3. If A = \begin{pmatrix} 2 & 3\\ 3 & 5 \end{pmatrix} (1) 12 (2) 16 (3) 24 (4) 28
Ans: (2)
Q4. The coefficient of x⁴⁸ in (1+x) + 2(1+x)^2 + 3(1+x)^3 + \dots + 100(1+x)^{100} (1) 100·¹⁰¹C₄₉ − ¹⁰¹C₅₀ (2) ¹⁰⁰C₅₀ + ¹⁰¹C₄₉ (3) 100·¹⁰⁰C₄₉ − ¹⁰⁰C₄₈ (4) 100·¹⁰⁰C₄₉ − ¹⁰⁰C₅₀
Ans: (1)
Q5. If the sum of the first 4 terms of an AP is 6 and the sum of 6 terms is 4, then the sum of the first 12 terms of an AP is (1) −22 (2) −21 (3) −23 (4) −24
Ans: (1)
Q6. The number of real solutions of the equation x|x+4| + 3|x+2| + 10 = 0 (1) 1 (2) 4 (3) 3 (4) 2
Ans: (1)

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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