D and F Block Elements MCQs for NEET 2026 | Important Questions
D & F Block Elements – NEET 2026 Practice MCQs
The catalytic activity of transition metals and their compounds is ascribed mainly to
their magnetic behaviour
their unfilled d-orbitals
their ability to adopt variable oxidation states
their chemical reactivity
Identify the alloy containing a non-metal as a constituent in it.
Invar
Steel
Bell metal
Bronze
The reaction of aqueous KMnO
4
with H
2
O
2
in acidic conditions gives
Mn
4+
and O
2
Mn
2+
and O
2
Mn
2+
and O
3
Mn
4+
and MnO
2
The reason for greater range of oxidation states in actinoids is attributed to
actinoid contraction
5f, 6d and 7s levels having comparable energies
4f and 5d levels being close in energies
the radioactive nature of actinoids
The stability of Cu
2+
is more than Cu
+
salts in aqueous solution due to –
enthalpy of atomization
hydration energy
second ionisation enthalpy
first ionisation enthalpy
The incorrect statement among the following is :
Actinoids are highly reactive metals, especially when finely divided.
Actinoid contraction is greater for element to element than lanthanoid contraction.
Most of the trivalent Lanthanoid ions are colorless in the solid state.
Lanthanoids are good conductors of heat and electricity.
The UV-visible absorption bands in the spectra of lanthanoid ions are 'X', probably because of the excitation of electrons involving 'Y'. The 'X' and 'Y', respectively, are :
Broad and f orbitals
Narrow and f orbitals
Broad and d and f orbitals
Narrow and d orbitals
Acidified K
2
Cr
2
O
7
solution turns green when Na
2
SO
3
is added to it. This is due to the formation of
Cr
2
(SO
4
)
3
CrO
4
2−
Cr
2
(SO
3
)
3
CrSO
4
Identify the incorrect statement.
PEt
3
and AsPH
3
as ligands can form dπ–dπ bond with transition metals
The N–N single bond is as strong as the P–P single bond
Nitrogen has unique ability to form pπ–pπ multiple bonds with nitrogen, carbon and oxygen
Nitrogen cannot form dπ–pπ bond as other heavier elements of its group
Which one of the following statements is correct when SO
2
is passed through acidified K
2
Cr
2
O
7
solution?
SO
2
is reduced.
Green Cr
2
(SO
4
)
3
is formed.
The solution turns blue.
The solution is decolourised.
SUBMIT TEST
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