JEE Main PYQs Mole Concept – Some Basic Concepts of Chemistry | NEET JEE Rankers

Fortification of food with iron is done using FeSO₄·7H₂O. The mass in grams of the FeSO₄·7H₂O required to achieve 12 ppm of iron in 150 kg of wheat is ______ (Nearest integer)

Given: Molar mass of Fe, S and O respectively are 56, 32 and 16 g mol⁻¹

Step 1: Calculate the mass of iron required

12 ppm means 12 mg of iron per kg of wheat.

Step 2: Calculate total iron needed for 150 kg wheat

Iron required = 12 × 150 = 1800 mg = 1.8 g

Step 3: Calculate molar mass of FeSO₄·7H₂O

FeSO₄ = 56 + 32 + (4 × 16) = 152 g mol⁻¹
7H₂O = 7 × 18 = 126 g mol⁻¹
Total molar mass = 152 + 126 = 278 g mol⁻¹

Step 4: Calculate fraction of iron in FeSO₄·7H₂O

Fraction of Fe = 56 / 278

Step 5: Calculate mass of FeSO₄·7H₂O required

Required mass = 1.8 × (278 / 56) ≈ 8.93 g

✅ Final Answer: 9 g

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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