Fortification of food with iron is done using FeSO₄·7H₂O. The mass in grams of the FeSO₄·7H₂O required to achieve 12 ppm of iron in 150 kg of wheat is ______ (Nearest integer)
Given: Molar mass of Fe, S and O respectively are 56, 32 and 16 g mol⁻¹
12 ppm means 12 mg of iron per kg of wheat.
Iron required = 12 × 150 = 1800 mg = 1.8 g
FeSO₄ = 56 + 32 + (4 × 16) = 152 g mol⁻¹
7H₂O = 7 × 18 = 126 g mol⁻¹
Total molar mass = 152 + 126 = 278 g mol⁻¹
Fraction of Fe = 56 / 278
Required mass = 1.8 × (278 / 56) ≈ 8.93 g