A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is ______

Mass Percent of Ethyl Alcohol Solution | JEE Mains Previous Year Question

Q. A solution is prepared by adding 1 mole ethyl alcohol in 9 mole water. The mass percent of solute in the solution is _______. (Integer answer) (Given : Molar mass in g mol⁻¹ Ethyl alcohol : 46 water : 18)

Step 1: Calculate mass of ethyl alcohol (solute)

Moles of ethyl alcohol = 1 Molar mass = 46 g mol⁻¹ Mass of ethyl alcohol = 1 × 46 = 46 g

Step 2: Calculate mass of water (solvent)

Moles of water = 9 Molar mass of water = 18 g mol⁻¹ Mass of water = 9 × 18 = 162 g

Step 3: Calculate total mass of solution

Total mass = 46 + 162 = 208 g

Step 4: Calculate mass percent of solute

Mass percent of solute = (mass of solute / total mass of solution) × 100

= (46 / 208) × 100 = 22.11%

Step 5: Integer value

Nearest integer value = 22

Final Answer: 22

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