H2SO4 Percentage to Molarity Numerical | JEE Mains PYQ | Mole Concept
Q. A solution of H₂SO₄ is 31.4% H₂SO₄ by mass and has a density of 1.25 g/mL. The molarity of the H₂SO₄ solution is ______ M (nearest integer)

[ Given molar mass of H₂SO₄ = 98 g mol⁻¹ ]
Explanation
Step 1: Assume 100 g of solution

Mass of H₂SO₄ = 31.4 g

Step 2: Calculate volume of solution

Density = Mass / Volume
Volume = 100 / 1.25 = 80 mL = 0.08 L

Step 3: Calculate moles of H₂SO₄

Moles = 31.4 / 98 = 0.32 mol

Step 4: Calculate molarity

M = moles / volume = 0.32 / 0.08 = 4 M

Correct Answer = 4

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

Scroll to Top