NaBr and KI evolve coloured vapours (Br₂ – brown, I₂ – violet). Hence, both are eliminated.
NaNO₃ gives nitric acid vapours (colourless). CaF₂ gives HF gas (colourless).
NaNO₃ is selected.
Na = 23
N = 14
O₃ = 16 × 3 = 48
Total molar mass = 23 + 14 + 48 = 85 g mol⁻¹
Correct Answer = 78
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.