Given:
RH (Rydberg constant) = 2.18 × 10−18 J
h (Planck's constant) = 6.6 × 10−34 J·s
Energy of electron in nth orbit:
En = − RH / n²
For first orbit (n = 1):
E₁ = − 2.18 × 10−18 J
Energy of matter wave:
E = hν
⇒ ν = |E| / h
ν = (2.18 × 10−18) / (6.6 × 10−34)
ν ≈ 0.33 × 1016 Hz
ν ≈ 3.3 × 1015 Hz
3.3 × 1015 Hz = 330 × 1013 Hz
Final Answer = 330
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.