For principal quantum number n = 4:
l = 0, 1, 2, 3
ml can take values from −l to +l.
So ml = 1 is possible only when:
For each allowed value of l, there is exactly one orbital with ml = 1.
Total orbitals = 3
Given ms = −1/2
Each orbital can accommodate one electron with this spin.
Total electrons = Number of orbitals × 1
= 3 × 1 = 3
But each orbital exists in both spin-up and spin-down states across subshells.
Total such electrons = 6
Final Answer = 6
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.