Given: mass of electron = 9 × 10⁻³¹ kg, Planck's constant (h) = 6.6 × 10⁻³⁴ J s
Correct Answer: 7
De Broglie wavelength of an electron is given by:
λ = h / √(2mK)
Substituting the given values:
h = 6.6 × 10⁻³⁴ J s
m = 9 × 10⁻³¹ kg
K = 4.50 × 10⁻²⁹ J
λ = 6.6 × 10⁻³⁴ / √(2 × 9 × 10⁻³¹ × 4.50 × 10⁻²⁹)
λ ≈ 7 × 10⁻⁵ m
Hence, the required wavelength of the electron is:
7 × 10⁻⁵ m