Given series is: ∑k=1∞ (−1)k+1 [ k(k+1) / k! ]
Expand the numerator: k(k+1) = k² + k
Split the term:
(k² + k)/k! = k/(k−1)! + 1/(k−1)!
So the series becomes sum of two standard exponential series:
∑ (−1)k+1 / (k−1)! + ∑ (−1)k+1 k/(k−1)!
Using known results of exponential series and simplifying,
the value of the given series is:
2 / e
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.