| List – I | List – II |
|---|---|
| A. Coefficient of viscosity | I. [ M L−1 T−2 ] |
| B. Surface tension | II. [ M L2 T−2 ] |
| C. Pressure | III. [ M L0 T−2 ] |
| D. Surface energy | IV. [ M L−1 T−1 ] |
Choose the correct answer from the options given below :
Correct Answer: A-IV, B-III, C-I, D-II
The dimensional formula of coefficient of viscosity is obtained from force per unit area per velocity gradient, which gives dimensions [ M L−1 T−1 ]. Hence A matches with IV.
Surface tension is force per unit length. Force has dimensions [ M L T−2 ], so surface tension has dimensions [ M T−2 ]. Hence B matches with III.
Pressure is force per unit area. Therefore, its dimensions are [ M L−1 T−2 ]. Hence C matches with I.
Surface energy is energy, and energy has dimensions [ M L2 T−2 ]. Hence D matches with II.
Therefore, the correct matching is A-IV, B-III, C-I, D-II.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.