A. CH4 + O2 Mo2O3, Δ →
B. 2CH3CH3 + 3O2 (CH3COO)2Mn, Δ →
C. (CH3)3CH KMnO4 →
D. 2CH4 + O2 Cu / 523 K / 100 atm →
E. CH3 – CH = CH – CH3 KMnO4 / H+ →
Choose the correct answer from the options given below :
Correct Answer: C and D Only
Reaction C involves oxidation of isobutane with KMnO4, which leads to formation of tert-butanol under controlled conditions.
Reaction D represents controlled oxidation of methane using Cu catalyst at high pressure and temperature, producing methanol.
Reaction A produces formaldehyde, not alcohol.
Reaction B results in formation of aldehydes and acids, not alcohols.
Reaction E with acidic KMnO4 causes oxidative cleavage of alkene, forming ketones or acids instead of alcohols.
Hence, alcohols are produced only in reactions C and D.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.