Λm = Λ°m − Ac1/2
Molar conductivity values of the solutions of strong electrolyte AB at 18°C are given below :
| c [mol L−1] | 0.04 | 0.09 | 0.16 | 0.25 |
|---|---|---|---|---|
| Λm [S cm2 mol−1] | 96.1 | 95.7 | 95.3 | 94.9 |
The value of constant A based on the above data [in S cm2 mol−1 /(mol/L)1/2] unit is ________.
Correct Answer: 4
For a strong electrolyte, the molar conductivity follows the relation:
Λm = Λ°m − A√c
Using two given data points:
For c = 0.04 mol L−1, √c = 0.2 and Λm = 96.1
For c = 0.25 mol L−1, √c = 0.5 and Λm = 94.9
Difference in molar conductivity:
96.1 − 94.9 = 1.2
Difference in √c:
0.5 − 0.2 = 0.3
Hence, the value of constant A is:
A = 1.2 / 0.3 = 4
Therefore, the value of constant A is 4.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.