Three persons enter in a lift at the ground floor. The lift will go up to 10th floor

Q. Three persons enter in a lift at the ground floor.

The lift will go up to 10th floor. The number of ways, in which the three persons can exit the lift at three different floors, if the lift does not stop at first, second and third floors, is equal to ______.

Correct Answer: 210

Explanation

The lift does not stop at the first, second and third floors.

So the possible floors where a person can exit are:

4, 5, 6, 7, 8, 9, 10

Total available floors = 7

Three persons must exit at three different floors.

The number of ways of choosing 3 different floors out of 7 is:

${}^7C_3 = 35$

The three persons are distinct, so they can exit in:

$3! = 6$ ways

Hence, total number of ways:

$35 \times 6 = 210$

Therefore, the required number of ways is:

$210$

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