The electric field of an electromagnetic wave travelling through a medium is given by E(x,t) = 25 sin (2.0 × 10^15 t − 10^7 x)

Q. The electric field of an electromagnetic wave travelling through a medium is given by

E(x, t) = 25 sin (2.0 × 1015 t − 107 x) n̂

then the refractive index of the medium is ______.

(All given measurement are in SI units)

(A) 2

(B) 1.2

(C) 1.5

(D) 1.7

Correct Answer: 1.5

Explanation

The standard equation of an electromagnetic wave is:

E(x, t) = E0 sin (ωt − kx)

Comparing it with the given equation:

ω = 2.0 × 1015 rad s−1
k = 107 m−1

The speed of the electromagnetic wave in the medium is:

v = ω / k

v = (2.0 × 1015) / (107) = 2.0 × 108 m s−1

Refractive index of the medium is given by:

n = c / v

n = (3.0 × 108) / (2.0 × 108) = 1.5

Hence, the refractive index of the medium is:

1.5

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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