Consider the above reaction A. The reaction proceeds through a more stable radical intermediate. B. The role of peroxide is to generate H• (Hydrogen radical). C. During this reaction, benzene is formed as a byproduct. D. 1-Bromo-2-phenylethane is formed as the minor product. E. The same reaction in absence of peroxide proceeds via carbocation intermediate. Identify the correct statements. Choose the correct answer from the options given below :

Identify the correct statements for the reaction Ph − CH = CH₂ in presence of peroxide and HBr.

Q. Ph − CH = CH₂ →
(PhCOO)₂ / HBr Product

Consider the above reaction

A. The reaction proceeds through a more stable radical intermediate.

B. The role of peroxide is to generate H• (Hydrogen radical).

C. During this reaction, benzene is formed as a byproduct.

D. 1-Bromo-2-phenylethane is formed as the minor product.

E. The same reaction in absence of peroxide proceeds via carbocation intermediate.

Identify the correct statements. Choose the correct answer from the options given below :

(A) A & E Only

(B) A, B & D Only

(D) C, D & E Only

Correct Answer: (C)

Explanation

In the presence of peroxide, addition of HBr to alkene occurs via a free radical mechanism known as the peroxide effect.

The reaction proceeds through a benzylic radical intermediate, which is highly stable due to resonance, hence statement A is correct.

Peroxide generates Br• radicals, not hydrogen radicals, so statement B is false.

During initiation, phenyl radical abstracts hydrogen to form benzene as a byproduct, therefore statement C is correct.

The major product formed is anti-Markovnikov product, hence 1-bromo-2-phenylethane is the major product, not minor, so statement D is false.

In absence of peroxide, the reaction follows ionic mechanism via carbocation intermediate, hence statement E is correct.

Thus, the correct statements are A, C and E only.

Explanation

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