Correct Answer: 2
For a closed organ pipe, only odd harmonics are present. The frequency of the nth harmonic of a closed pipe is given by:
fn = n v / (4Lc) (n = 1, 3, 5, ...)
Here, the fifth harmonic of the closed pipe corresponds to n = 5.
Frequency of the fifth harmonic of closed pipe:
f = 5v / (4Lc)
For an open organ pipe, all harmonics are present and the frequency of the first harmonic is:
f = v / (2Lo)
Since the two frequencies are in unison, they are equal:
5v / (4Lc) = v / (2Lo)
Cancel v from both sides:
5 / (4Lc) = 1 / (2Lo)
Cross-multiplying:
10Lo = 4Lc
Lc / Lo = 10 / 4 = 5 / 2
Given ratio = 5 / x
So,
5 / x = 5 / 2
x = 2
Hence, the value of x = 2.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.