Correct Answer: 25 Ω
Resistance of galvanometer, G = 100 Ω
Full scale deflection current of galvanometer,
Ig = 1 mA = 0.001 A
Required full scale current of ammeter,
I = 5 mA = 0.005 A
To convert a galvanometer into an ammeter, a shunt resistance S is connected in parallel such that:
S = (Ig × G) / (I − Ig)
Substitute the given values:
S = (0.001 × 100) / (0.005 − 0.001)
S = 0.1 / 0.004
S = 25 Ω
Hence, the resistance required to convert the galvanometer into an ammeter is 25 Ω.
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