(A) \( 2\pi \sqrt{\dfrac{\rho A}{Mg}} \)
(B) \( \pi \sqrt{\dfrac{2M}{\rho Ag}} \)
(C) \( 2\pi \sqrt{\dfrac{M}{\rho Ag}} \)
(D) \( \pi \sqrt{\dfrac{\rho A}{Mg}} \)
Correct Answer: \( 2\pi \sqrt{\dfrac{M}{\rho A g}} \)
At equilibrium, the weight of the block is balanced by the buoyant force.
When the block is depressed downward by a small distance \(x\), the volume of liquid displaced increases by
This causes an additional buoyant force acting upward given by
This force acts as a restoring force, hence
Thus, the motion of the block is simple harmonic motion.
For SHM, the time period is
Substituting the value of \(k\),
Therefore, the period of oscillation is \[ \boxed{2\pi \sqrt{\dfrac{M}{\rho A g}}} \]
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.