Hybridisation shape and spin only magnetic moment statements for coordination compounds
Q. Given below are two statements:

Statement I: Hybridisation, shape and spin only magnetic moment of K₃[Co(CO₃)₃] is sp³d², octahedral and 4.9 BM respectively.

Statement II: Geometry, hybridisation and spin only magnetic moment values (BM) of the ions [Ni(CN)₄]²⁻, [MnBr₄]²⁻ and [CoF₆]³⁻ respectively are square planar, tetrahedral, octahedral; dsp², sp³, sp³d² and 0, 5.9, 4.9.

In the light of the above statements, choose the correct answer from the options given below.

(A) Both Statement I and Statement II are false

(B) Statement I is true but Statement II is false

(C) Both Statement I and Statement II are true

(D) Statement I is false but Statement II is true

Correct Answer: Both Statement I and Statement II are true

Explanation

In K₃[Co(CO₃)₃], cobalt is in +3 oxidation state with electronic configuration d⁶. Carbonate acts as a weak field ligand, so pairing does not occur. The complex forms an octahedral geometry with sp³d² hybridisation and has four unpaired electrons, giving a spin only magnetic moment close to 4.9 BM. Hence, Statement I is correct.

For [Ni(CN)₄]²⁻, CN⁻ is a strong field ligand, causing pairing of electrons and leading to square planar geometry with dsp² hybridisation and zero magnetic moment. For [MnBr₄]²⁻, Br⁻ is a weak field ligand, resulting in tetrahedral geometry with sp³ hybridisation and five unpaired electrons giving a magnetic moment of about 5.9 BM. For [CoF₆]³⁻, F⁻ is a weak field ligand, producing an octahedral complex with sp³d² hybridisation and four unpaired electrons corresponding to a magnetic moment of about 4.9 BM. Hence, Statement II is also correct.

Therefore, both Statement I and Statement II are true.

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