| List-I Chloro derivative |
List-II Example |
|---|---|
| A. Vinyl Chloride | I. CH₂ = CH – CH₂Cl |
| B. Benzyl Chloride | II. CH₃ – CH(Cl)CH₃ |
| C. Alkyl Chloride | III. CH₂ = CHCl |
| D. Allyl Chloride | IV. C₆H₅ – CH(Cl) – CH₃ |
Choose the correct answer from the options given below:
(A) A-III, B-IV, C-I, D-II
(B) A-IV, B-I, C-III, D-II
(C) A-III, B-IV, C-II, D-I
(D) A-I, B-II, C-IV, D-III
Correct Answer: A-III, B-IV, C-II, D-I
Vinyl chloride has chlorine directly attached to an sp² carbon of a double bond. Its formula is CH₂ = CHCl, which corresponds to III.
Benzyl chloride has chlorine attached to a carbon next to a benzene ring. The given structure C₆H₅ – CH(Cl) – CH₃ represents benzyl-type substitution, corresponding to IV.
Alkyl chloride contains chlorine attached to a saturated sp³ carbon atom. CH₃ – CH(Cl)CH₃ is an alkyl chloride, corresponding to II.
Allyl chloride has chlorine attached to a carbon adjacent to a double bond. CH₂ = CH – CH₂Cl represents allyl chloride, corresponding to I.
Thus, the correct matching is A-III, B-IV, C-II, D-I.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.