K > Mg > Al > B metallic character and atomic radius vs ionic radius assertion reason question
Q. Given below are two statements:

Statement I: K > Mg > Al > B is the correct order in terms of metallic character.

Statement II: Atomic radius is always greater than the ionic radius for any element.

In the light of the above statements, choose the correct answer from the options given below.

(A) Both Statement I and Statement II are false

(B) Statement I is false but Statement II is true

(C) Statement I is true but Statement II is false

(D) Both Statement I and Statement II are true

Correct Answer: (C)

Explanation

Statement I:

Metallic character increases down a group and decreases across a period.

Potassium (K) is an alkali metal (Group 1) → highest metallic character among given elements.

Magnesium (Mg) is in Group 2 → less metallic than K but more than Al.

Aluminium (Al) is in Group 13 → metallic but less than Mg.

Boron (B) is a metalloid → least metallic character.

Therefore, the order:

K > Mg > Al > B

Statement I is true.


Statement II:

This statement is incorrect.

For cations:

Ionic radius < atomic radius (example: Na⁺ < Na)

For anions:

Ionic radius > atomic radius (example: Cl⁻ > Cl)

Hence, atomic radius is not always greater than ionic radius.

Statement II is false.

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