Which of the following statements are TRUE about Haloform reaction? A. Sodium hypochlorite reacts with KI to give KOI. B. KOI is a reducing agent. C. α, β-unsaturated methyl ketone (CH3–CH=CH–CO–CH3) will give iodoform reaction. D. Isopropyl alcohol will not give iodoform test. E. Methanoic acid will give positive iodoform test.

Which of the following statements are TRUE about Haloform reaction?

Q. Which of the following statements are TRUE about Haloform reaction?

A. Sodium hypochlorite reacts with KI to give KOI.

B. KOI is a reducing agent.

C. α, β-unsaturated methyl ketone $$ \mathrm{CH_3-CH=CH-CO-CH_3} $$ will give iodoform reaction.

D. Isopropyl alcohol will not give iodoform test.

E. Methanoic acid will give positive iodoform test.

Correct Answer: A & C Only

Explanation

Statement A is true. Sodium hypochlorite reacts with potassium iodide to form potassium hypoiodite (KOI), which is the active halogenating species in the haloform reaction.

Statement B is false. KOI acts as an oxidizing and iodinating agent, not as a reducing agent.

Statement C is true. Any compound containing a –COCH₃ (methyl ketone) group gives the iodoform reaction. In an α, β-unsaturated methyl ketone, the presence of the methyl ketone unit is sufficient for the reaction.

Statement D is false. Isopropyl alcohol is oxidized to acetone, which is a methyl ketone; therefore, isopropyl alcohol gives a positive iodoform test.

Statement E is false. Methanoic acid does not contain a methyl ketone group and hence does not give the iodoform test.

Therefore, only statements A and C are correct.

Explanation

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