Let us check each statement one by one.
Statement A:
For 2412Mg:
Atomic number = 12 → Number of protons = 12
Number of neutrons = $24 - 12 = 12$
The statement says 24 protons and 12 neutrons, which is incorrect.
So, Statement A is incorrect.
Statement B:
Using relation:
$$ \lambda = \frac{c}{\nu} $$
$$ \lambda = \frac{3.0 \times 10^8}{4.5 \times 10^{15}} = 0.667 \times 10^{-7} = 6.67 \times 10^{-8}\ \text{m} $$
This matches the given value.
So, Statement B is correct.
Statement C:
Energy of radiation:
$$ E \propto \frac{1}{\lambda} $$
$$ \frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1} = \frac{300}{900} = \frac{1}{3} $$
Thus,
$$ E_1 : E_2 = 1 : 3 $$
Given ratio is $3 : 1$, which is incorrect.
So, Statement C is incorrect.
Statement D:
Convert wavelength:
$$ 2000\ \text{pm} = 2 \times 10^{-9}\ \text{m} $$
Energy of one photon:
$$ E = \frac{hc}{\lambda} = \frac{6.626 \times 10^{-34} \times 3 \times 10^8}{2 \times 10^{-9}} \approx 9.94 \times 10^{-17}\ \text{J} $$
Number of photons:
$$ n = \frac{1}{9.94 \times 10^{-17}} \approx 1.0 \times 10^{16} $$
Given value is correct.
So, Statement D is correct.
Therefore, the incorrect statements are A and C only.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.