The system is water kept inside a microwave oven. When the oven is switched on, energy is supplied to the system, hence heat absorbed by the system is positive.
Therefore,
$$ q = +ve $$
As the water starts boiling, it expands against atmospheric pressure and does work on the surroundings. Hence, work done by the system is negative.
$$ w = -ve $$
According to the first law of thermodynamics,
$$ \Delta U = q + w $$
Since the magnitude of heat supplied is greater than the work done during heating and boiling, the internal energy of the system increases.
$$ \Delta U = +ve $$
Thus, the correct option is:
$$ \boxed{q = +ve,\; w = -ve,\; \Delta U = +ve} $$
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.