| List - I (Reaction of Glucose with) |
List - II (Product formed) |
|---|---|
| A. Hydroxylamine | I. Gluconic acid |
| B. Br2 water | II. Glucose pentacetate |
| C. Excess acetic anhydride | III. Saccharic acid |
| D. Concentrated HNO3 | IV. Glucoxime |
Choose the correct answer from the options given below :
Glucose is an aldose sugar and shows characteristic reactions due to the presence of an aldehyde group and multiple hydroxyl groups.
A. Reaction with Hydroxylamine
Aldehyde group of glucose reacts with hydroxylamine to form an oxime. Hence, the product formed is glucoxime.
So, A → IV
B. Reaction with Br₂ water
Bromine water is a mild oxidising agent. It oxidises the aldehyde group (–CHO) of glucose to carboxylic acid without affecting the alcohol groups, forming gluconic acid.
So, B → I
C. Reaction with excess acetic anhydride
All five –OH groups of glucose get acetylated in presence of excess acetic anhydride, forming glucose pentacetate.
So, C → II
D. Reaction with concentrated HNO₃
Concentrated nitric acid is a strong oxidising agent. It oxidises both the aldehyde group and the terminal –CH₂OH group of glucose to carboxylic acids, forming saccharic acid.
So, D → III
Therefore, the correct matching is:
A-IV, B-I, C-II, D-III
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.