XF3 behaves as a Lewis acid, which means the central atom has an incomplete octet and can accept an electron pair.
For EF3 acting as a Lewis acid (like BF3), the central atom forms three σ-bonds and has no lone pair.
Number of electron domains around X = 3
Hence, hybridization of X in XF3 is sp2.
YF3 behaves as a Lewis base, which means the central atom has at least one lone pair available for donation.
For EF3 acting as a Lewis base (like NF3), the central atom has three bond pairs and one lone pair.
Total electron domains around Y = 4
Hence, hybridization of Y in YF3 is sp3.
Therefore, the correct hybridizations are:
XF3 → sp2
YF3 → sp3
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.