The temperature at which the rate constants of the given below two gaseous reactions become equal is ____ K.
Q. The temperature at which the rate constants of the given below two gaseous reactions become equal is ____ K. (Nearest integer)

X \rightarrow Y,\quad k_1 = 10^6 e^{-\frac{30000}{T}}

P \rightarrow Q,\quad k_2 = 10^4 e^{-\frac{24000}{T}}

Given : \ln 10 = 2.303
Correct Answer: 1303 K

Step 1: Condition for Equality

Since k_1 = k_2,

\[ 10^6 e^{-\frac{30000}{T}} = 10^4 e^{-\frac{24000}{T}} \]

Step 2: Rearranging

\[ \frac{10^6}{10^4} = e^{-\frac{24000}{T} + \frac{30000}{T}} \]

\[ 10^2 = e^{\frac{6000}{T}} \]

Step 3: Taking Natural Log

\[ \ln(10^2) = \frac{6000}{T} \]

\[ 2 \ln 10 = \frac{6000}{T} \]

\[ 2 \times 2.303 = \frac{6000}{T} \]

\[ 4.606 = \frac{6000}{T} \]

Step 4: Solve for T

\[ T = \frac{6000}{4.606} \]

\[ T = 1303 \text{ K} \]

Related JEE Main Questions

Dissociation of a gas A₂ takes place according to the following chemical reaction. At equilibrium, the total pressure is 1 bar at 300 K. A₂(g) ⇌ 2A(g). The degree of dissociation of A₂(g) is given by (x × 10⁻²)¹ᐟ² where x = ____ .
The cycloalkene (X) on bromination consumes one mole of bromine per mole of (X) and gives the product (Y) in which C : Br ratio is 3 : 1. The percentage of bromine in the product (Y) is ____ %.
Sodium fusion extract of an organic compound (Y) with CHCl₃ and chlorine water gives violet color to the CHCl₃ layer. 0.15 g of (Y) gave 0.12 g of the silver halide precipitate in Carius method. Percentage of halogen in the compound (Y) is

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

Scroll to Top