Angular momentum of a particle about a point is:
\[ L = m (\vec{r} \times \vec{v}) \]
Magnitude form:
\[ L = mrv\sin\theta \]
Here, motion is along parallel tracks separated by 10 m.
So perpendicular distance between velocity of A and car B = 10 m
Step 1: Convert speeds into m/s
\[ 72 \text{ km/h} = \frac{72 \times 1000}{3600} \]
\[ = 20 \text{ m/s} \]
\[ 36 \text{ km/h} = 10 \text{ m/s} \]
Step 2: Relative velocity of A with respect to B
\[ v_{AB} = 20 - 10 \]
\[ v_{AB} = 10 \text{ m/s} \]
Step 3: Use angular momentum formula
\[ L = m v_{rel} \times d \]
\[ L = (10^3)(10)(10) \]
\[ L = 10^5 \text{ J·s} \]
Final Answer: 105 J·s
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.