Given below are two statements : Statement I : The correct order in terms of bond dissociation enthalpy is Cl2 > Br2 > F2 > I2. Statement II : The correct trend in the covalent character of the metal halides is [SnCl4 > SnCl2], [PbCl4 > PbCl2] and [UF4 > UF6].
Given below are two statements :

Statement I : The correct order in terms of bond dissociation enthalpy is Cl2 > Br2 > F2 > I2.

Statement II : The correct trend in the covalent character of the metal halides is [SnCl4 > SnCl2], [PbCl4 > PbCl2] and [UF4 > UF6].

In the light of the above statements, choose the correct answer from the options given below :
A. Both Statement I and Statement II are true
B. Both Statement I and Statement II are false
C. Statement I is false but Statement II is true
D. Statement I is true but Statement II is false
Correct Answer: D

Explanation

Statement I :

Bond dissociation enthalpy among halogens follows:

Cl2 > Br2 > F2 > I2

Although F–F bond is shorter, it is weaker than Cl–Cl due to strong lone pair–lone pair repulsions in the small F atom.

Thus, the given order is correct.

Statement I is true.


Statement II :

According to Fajans’ rule, covalent character increases with:

• Higher charge on cation

• Smaller size of cation

SnCl4 > SnCl2 ✔ (Sn⁴⁺ has higher charge than Sn²⁺)

PbCl4 > PbCl2 ✔ (Pb⁴⁺ has higher charge than Pb²⁺)

For uranium fluorides:

UF6 contains U⁶⁺ (higher charge)

UF4 contains U⁴⁺ (lower charge)

Higher oxidation state means greater polarization and more covalent character.

Therefore,

UF6 > UF4

But statement given says UF4 > UF6, which is incorrect.

Statement II is false.

Hence, Statement I is true but Statement II is false.

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