Given below are four compounds : (a) n-propyl chloride (b) iso-propyl chloride (c) sec-butyl chloride (d) neo-pentyl chloride Percentage of carbon in the one which exhibits optical isomerism is :
Q. Given below are four compounds :

(a) n-propyl chloride      (b) iso-propyl chloride

(c) sec-butyl chloride      (d) neo-pentyl chloride

Percentage of carbon in the one which exhibits optical isomerism is :
A. 46
B. 40
C. 52
D. 56
Correct Answer: C

Explanation

Check which compound shows optical isomerism.

n-propyl chloride → CH₃–CH₂–CH₂Cl → No chiral carbon.

iso-propyl chloride → (CH₃)₂CHCl → Two identical CH₃ groups → Not chiral.

sec-butyl chloride → CH₃–CHCl–CH₂–CH₃

The second carbon is attached to:

• CH₃

• C₂H₅

• Cl

• H

Four different groups → Chiral → Shows optical isomerism.

neo-pentyl chloride → (CH₃)₃C–CH₂Cl → No chiral carbon.

Thus, sec-butyl chloride exhibits optical isomerism.


Molecular formula of sec-butyl chloride:

C₄H₉Cl

Molar mass:

= 4(12) + 9(1) + 35.5

= 48 + 9 + 35.5

= 92.5 g mol⁻¹

Mass of carbon:

= 4 × 12 = 48 g

Percentage of carbon:

\[ \frac{48}{92.5} \times 100 \]

\[ ≈ 51.9 \% \approx 52 \% \]

Correct Option: C

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