Dual Nature of Radiation & Matter Quiz – JEE Main 2026 | NEET JEE Rankers
Dual Nature of Radiation & Matter – JEE Main Quiz
10 Questions | MCQ + Numerical | PYQ Based
Q1.
The de Broglie wavelength of an electron having kinetic energy E is λ. If kinetic energy becomes E/4, its wavelength will be:
√2 λ
2 λ
λ / 2
λ / √2
Q2.
Ratio of de Broglie wavelengths of proton and electron having same kinetic energy (mp = 1849 me):
1 : 43
1 : 62
2 : 43
1 : 30
Q3.
UV light of energy 4.13 eV is incident on a metal of work function 3.13 eV. Maximum kinetic energy of photoelectrons is:
4.13 eV
1 eV
7.26 eV
3.13 eV
Q4.
Threshold frequency of a metal with work function 6.63 eV is:
16 × 10¹⁵ Hz
16 × 10¹² Hz
1.6 × 10¹⁵ Hz
1.6 × 10¹² Hz
Q5.
Proton and electron have same de Broglie wavelength. Ratio of their kinetic energies (Kp : Ke):
1 : 1/1836
1 : √1836
1 : 1836
1 : 43
Q6.
In Franck–Hertz experiment, first dip is at 10.2 V. Wavelength of emitted light (nm):
Correct Answer:
122
nm
λ = hc / E = 1245 / 10.2 ≈ 122 nm
Q7.
An electron enters magnetic field B perpendicular to velocity. Its de Broglie wavelength after time t will be:
λ₀ / √(1 − e²B²t²/m²)
λ₀
λ₀ √(1 + e²B²t²/m²)
λ₀ / √(1 + e²B²t²/m²)
Q8.
Proton and electron will have same de Broglie wavelength when ratio of their momenta is:
1 : 1
1 : 43
1 : 1849
43 : 1
Q9.
Ratio of de Broglie wavelengths of electron in ground state to third excited state of hydrogen is:
4
3
9
16
Q10.
A proton has same energy as photon of wavelength λ. Ratio of de Broglie wavelength of proton to photon wavelength is:
(1/c)√(E/mp)
(1/c)√(2E/mp)
(1/2c)√(E/mp)
(1/c)√(E/2mp)
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