Zener breakdown: in heavily doped junctions with narrow depletion layers. Strong electric field in narrow depletion layer causes valence electrons to tunnel → breakdown at low reverse voltage (~5V). Avalanche breakdown occurs in lightly doped junctions at higher voltage.
Q2
On increasing temperature of a semiconductor:
AElectrons decrease, resistance increases
BBoth increase
CElectrons increase, resistance decreases
DBoth decrease
✅ Correct: C
In semiconductors, increasing temperature generates more electron-hole pairs (thermal excitation across band gap). More carriers → conductivity increases → resistance decreases. This is the opposite of metals (where resistance increases with temperature).
Q3
Diode: forward drop 0.5 V, max current 10 mA, battery 1.5 V. Minimum series resistance:
p-type semiconductor is formed by doping with trivalent impurities (B, Al, Ga). Each dopant atom creates a hole → holes are majority carriers, electrons are minority carriers.
Q7
Truth table of NAND gate output for inputs (1,1):
A1
B0
CDepends on frequency
DUndefined
✅ Correct: B
NAND gate: output = NOT(A·B). For (1,1): A·B = 1, NOT(1) = 0. NAND output is 0 only when both inputs are 1; otherwise output is 1.
Q8
For transistor in common emitter configuration, current gain \(\beta = I_C/I_B\). If \(I_B = 50\)μA and \(\beta = 100\), collector current:
Depletion region in p-n junction is formed due to:
AApplication of external voltage
BDiffusion of majority carriers
CDrift of minority carriers
DThermal generation
✅ Correct: B
Depletion region forms by diffusion of majority carriers: electrons from n-side diffuse to p-side, holes from p-side diffuse to n-side. They recombine, leaving behind fixed ionized donor/acceptor atoms → built-in electric field.
Q10
In forward bias of p-n junction:
ADepletion region widens
BBarrier potential increases
CMajority carrier current flows
DMinority carrier current flows
✅ Correct: C
Forward bias: p connected to +ve, n to -ve terminal. Barrier potential decreases → majority carriers flow across junction → large current. In reverse bias: depletion region widens, only tiny minority carrier current flows.
Q11
Output of OR gate with inputs A=1, B=0:
A0
B1
CUndefined
DSame as input A
✅ Correct: B
OR gate: output = A+B (logical OR). For A=1, B=0: output \(= 1+0 = \mathbf{1}\). OR output is 0 only when both inputs are 0.
Q12
n-type semiconductor is formed by doping silicon with:
ABoron
BAluminium
CPhosphorus
DGallium
✅ Correct: C
n-type: doped with pentavalent (Group 15) elements: Phosphorus (P), Arsenic (As), Antimony (Sb). Extra electron becomes majority carrier. p-type: trivalent (Group 13): Boron, Aluminium, Gallium.
Q13
Zener diode is used as:
ARectifier
BAmplifier
CVoltage regulator
DOscillator
✅ Correct: C
Zener diode in reverse bias breakdown maintains constant voltage across it. Used as voltage regulator — output voltage remains constant despite variations in input or load. Connected in parallel with load.
Q14
In a half-wave rectifier, output frequency for 50 Hz input:
A25 Hz
B50 Hz
C100 Hz
D200 Hz
✅ Correct: B
Half-wave rectifier passes only alternate half cycles → output frequency = same as input = 50 Hz. Full-wave rectifier passes both half cycles → output frequency = 100 Hz (double the input).
Q15
Boolean expression for NAND gate:
A\(\overline{A+B}\)
B\(\overline{AB}\)
C\(AB\)
D\(A+B\)
✅ Correct: B
NAND gate: \(Y = \overline{AB} = \overline{A\cdot B}\). De Morgan's theorem: \(\overline{AB} = \bar{A}+\bar{B}\). NOR gate: \(Y = \overline{A+B}\). \(\mathbf{\overline{AB}}\).
Q16
Intrinsic semiconductor at absolute zero (0 K):
ABehaves as conductor
BBehaves as perfect insulator
CHas maximum conductivity
DHas few charge carriers
✅ Correct: B
At 0 K, all valence electrons are in valence band, conduction band is completely empty. No thermal energy to excite electrons across band gap. Intrinsic semiconductor behaves as perfect insulator at 0 K.
Q17
Common emitter transistor: voltage gain = \(\beta R_C/R_i\). If \(\beta = 50\), \(R_C = 2\) kΩ, \(R_i = 500\) Ω:
A100
B200
C50
D400
✅ Correct: B
Voltage gain \(= \beta R_C/R_i = 50\times2000/500 = 50\times4 = \mathbf{200}\).
Q18
Energy band gap of silicon at room temperature (~eV):
A0.67
B1.1
C5.4
D3.2
✅ Correct: B
Silicon band gap \(\approx \mathbf{1.1\text{ eV}}\) at room temperature. Germanium: 0.67 eV. Diamond: 5.4 eV. GaN: 3.4 eV. Band gap of Si makes it ideal for room temperature semiconductor devices.
Q19
NOR gate is called universal gate because:
AIt has highest speed
BIt can realize any logic function
CIt has two inputs
DIt consumes least power
✅ Correct: B
NOR gate (like NAND) is a universal gate because any Boolean function can be realized using only NOR gates. NOT: NOR with both inputs same. AND: three NORs. OR: two NORs. This simplifies IC manufacturing.
Q20
In full-wave bridge rectifier, number of diodes used:
A1
B2
C4
D6
✅ Correct: C
Bridge rectifier uses 4 diodes arranged in a bridge configuration. During positive half cycle: 2 diodes conduct. During negative half cycle: other 2 diodes conduct. Both half cycles appear at output with same polarity. No centre-tapped transformer needed.
R
Roshan
Expert · 5 Years Experience
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