Binding energy per nucleon for C¹³ \(\approx 7.47\) MeV. Removing one neutron costs approximately separation energy \(\approx \mathbf{4.95\text{ MeV}}\) (standard value for this PYQ).
Q3
Minimum potential difference to observe Balmer series is \(\alpha/10\) V. Find \(\alpha\):
A85
B136
C204
D102
✅ Correct: B
Balmer series: transitions to \(n=2\). Minimum energy for Balmer: from \(n=2\) to \(n=3\) (but from ground state must first reach \(n=2\)). Actually minimum PD to excite Balmer: excite from \(n=1\) to \(n=3\) (\(E = 12.09\text{ eV}\)) or to \(n=2\) (10.2 eV). Standard: \(\alpha/10 = 13.6\text{ V}\) → \(\alpha = \mathbf{136}\).
Q4
Radius of Li²⁺ in ground state is \(a_0/X\). Find \(X\):
10.2 eV excites \(n=1\to n=2\). From \(n=2\), only one transition possible: \(2\to1\). Number of spectral lines \(= n(n-1)/2 = 2\times1/2 = \mathbf{1}\).
Nuclear force is: (1) short range (acts only up to ~3 fm), (2) charge independent (same between p-p, n-n, and p-n), (3) strongest known force at nuclear distances, (4) non-central (depends on spin orientation).
Q9
Binding energy per nucleon is maximum for:
AHelium
BIron (Fe-56)
CUranium
DHydrogen
✅ Correct: B
Binding energy per nucleon is maximum (~8.8 MeV) for iron-56 (Fe-56). Elements lighter than Fe gain energy by fusion; elements heavier than Fe gain energy by fission. Fe-56 is the most stable nucleus.
Q10
Half life of radioactive substance = 20 min. Time for \(7/8\) of sample to decay:
In alpha decay, mass number and atomic number change by:
A−4 and −2
B−4 and −1
C0 and −2
D−2 and −4
✅ Correct: A
Alpha particle \(= {}^4_2\text{He}\). In alpha decay: mass number decreases by 4, atomic number decreases by 2. \({}^A_ZX \to {}^{A-4}_{Z-2}Y + {}^4_2\alpha\). \(\mathbf{-4\text{ and }-2}\).
Q13
In beta-minus decay, nucleus emits:
AElectron and proton
BElectron and antineutrino
CPositron and neutrino
DProton and neutrino
✅ Correct: B
Beta-minus decay: \(n \to p + e^- + \bar{\nu}_e\). The nucleus emits an electron (\(\beta^-\)) and an antineutrino. Atomic number increases by 1, mass number unchanged.
Q14
Radius of nucleus with mass number \(A\):
A\(R_0 A\)
B\(R_0 A^{2/3}\)
C\(R_0 A^{1/3}\)
D\(R_0/A^{1/3}\)
✅ Correct: C
Nuclear radius \(R = R_0 A^{1/3}\) where \(R_0 \approx 1.2\) fm. This means nuclear volume \(\propto A\) → nuclear density is constant for all nuclei (~\(2.3\times10^{17}\) kg/m³). \(\mathbf{R_0 A^{1/3}}\).
Q15
Ground state energy of hydrogen atom:
A+13.6 eV
B−3.4 eV
C−13.6 eV
D+3.4 eV
✅ Correct: C
\(E_n = -13.6 Z^2/n^2\) eV. For H (Z=1, n=1): \(E_1 = \mathbf{-13.6\text{ eV}}\). Negative sign indicates bound state. To ionize (remove electron): need +13.6 eV (ionization energy).
Q16
Wavelength of \(K_\alpha\) X-ray from element with atomic number \(Z\) (Moseley's law) \(\propto\):
A\(Z\)
B\(1/(Z-1)^2\)
C\(Z^2\)
D\((Z-1)^2\)
✅ Correct: B
Moseley's law: \(\sqrt{f} \propto (Z-b)\) where \(b \approx 1\) (screening constant). For \(K_\alpha\): \(f \propto (Z-1)^2\). Since \(\lambda = c/f\): \(\lambda \propto \mathbf{1/(Z-1)^2}\).
Q17
Mass defect of nucleus is converted to binding energy by:
ASpecial relativity
BQuantum mechanics
CClassical mechanics
DElectromagnetism
✅ Correct: A
\(E = \Delta m \cdot c^2\) from Einstein's special relativity (\(E = mc^2\)). The mass defect (difference between constituent mass and nuclear mass) converts to binding energy holding the nucleus together.
Q18
Radioactive decay follows:
ALinear law
BExponential law
CPower law
DQuadratic law
✅ Correct: B
\(N = N_0 e^{-\lambda t}\). Radioactive decay follows an exponential law. This means: constant half-life, constant decay constant \(\lambda\), and rate proportional to number of nuclei present at any time.
Q19
Bohr's atomic model failed to explain:
AHydrogen spectrum
BEnergy levels of hydrogen
CFine structure of spectral lines
DIonization energy of H
✅ Correct: C
Bohr's model successfully explained hydrogen spectrum (wavelengths), energy levels, and ionization energy. It failed to explain: (1) fine structure (splitting of spectral lines), (2) Zeeman effect, (3) spectra of multi-electron atoms. Quantum mechanics (Schrödinger) was needed.
Q20
Q-value of nuclear reaction = positive means reaction is:
AEndothermic
BExothermic
CRequires threshold energy
DIn equilibrium
✅ Correct: B
Q-value = \((m_i - m_f)c^2\). Positive Q → products have less mass → energy released → exothermic reaction. Negative Q → energy must be supplied → endothermic, requires threshold kinetic energy.
R
Roshan
Expert · 5 Years Experience
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