Biomolecules

Complete Notes

Contents Introduction — Living Chemicals Comparison of Elements: Non-living vs Living Chemical Analysis of a Living Tissue Primary and Secondary Metabolites Carbohydrates Amino Acids and Proteins Lipids Enzymes Dynamic State of Body Constituents & ATP Practice Questions Download Notes

Introduction — Living Chemicals/Biomolecules

All organisms are made up of some chemicals which are called biomolecules. There is wide variety in living organisms — herbivores, carnivores — but all of them are made up of the same chemicals, i.e. the same elements and compounds.

Biomicromolecules and Biomacromolecules

Biomicromolecules: molecular weight 18–800 Dalton. Monomeric substances such as amino acids, simple sugars, nucleotides.

Biomacromolecules: Polymeric, except lipid. Examples: Protein, Carbohydrate, Nucleic acid.

A Comparison of Elements Present (% of weight) — Non-living and Living Matter

ElementEarth's CrustHuman Body
Hydrogen (H)0.1418.5
Carbon (C)0.0346.6
Oxygen (O)0.565.0
Nitrogen (N)very little3.3
Sulphur (S)0.030.3
Sodium (Na)2.60.2
Calcium (Ca)3.61.5
Magnesium (Mg)2.10.1
Silicon (Si)27.7negligible

Analyse of Living Cell — Acid Soluble Pool & Acid Insoluble Pool

If a living tissue is ground in trichloroacetic acid (TCA) using a mortar and pestle, a thick slurry is obtained. On filtering this slurry through cheesecloth or filter paper, two fractions are separated:

Filtrate (Acid Soluble Pool): Contains inorganic constituents — Na⁺, K⁺, Ca²⁺, Mg²⁺ ions; inorganic compounds such as NaCl, CaCO₃, PO₄³⁻, SO₄²⁻; and biomicromolecules such as amino acids, simple sugars, nucleotides, vitamins.
Retentate (Acid Insoluble Pool): Contains biomacromolecules — Proteins, Carbohydrates (polysaccharides), Nucleic acids, Lipids.

Inorganic Constituents of a Living Organism

Component ions: Sodium, Potassium, Calcium, Magnesium, and Water.

Average Chemical Composition of a Cell

Component% of Total Cellular Mass
Water70-90
Proteins10-15
Carbohydrates3
Lipids2
Nucleic Acids5-7
Ions1

Primary and Secondary Metabolites

Primary Metabolites: Produced in all organisms. Role: Growth, Development, Reproduction etc. e.g. Protein, Carbohydrate.
Secondary Metabolites: Produced during stationary phase, in small quantity, in some species (Plant, Fungus, Bacteria). They produce different types of substances and provide indirect structural support.

Examples of Secondary Metabolites

Carbohydrate

Carbo: Carbon, Hydrate: Hydrate of water.

It is an Aldehyde or Ketone: Glucose, Galactose — Aldo (C:O 1:1, CH-O:H); Fructose — Ketone.

Types of Carbohydrate

Monosaccharide

Cannot be further hydrolysed. For C3 to C7 carbon atoms: C₃H₆O₃, C₄H₈O₄, C₅H₁₀O₅, C₆H₁₂O₆.

No. of CarbonClassificationExamples
3TriosesGlyceraldehyde, Dihydroxyacetone
4TetrosesErythrose, Erythrulose
5PentosesRibose, Xylose, Ribulose, Xylulose
6HexosesGlucose, Galactose, Fructose
7HeptosesSedoheptulose

Structure — Open Chain and Ring Forms

Monosaccharides can exist in open chain form as well as ring forms. Glucose forms a six-membered ring (Pyranose ring). Fructose forms a five-membered ring (Furanose ring).

Anomers

The two ring forms which differ in position (configuration) at C1 carbon are called Anomers — α-position and β-position (e.g., α-D-Glucose, β-D-Glucose).

Isomers of Monosaccharide

Molecules with the same molecular formula but different structural form. Epimers — differ only at one position, e.g. Glucose and Galactose, Glucose and Mannose.

Disaccharides

A disaccharide is formed when two monosaccharides are joined together by a glycosidic linkage, with the loss of one water molecule.

DisaccharideCompositionLinkageReducing/Non-Reducing
Maltose (Malt Sugar)Glucose + Glucoseα(1→4)Reducing
Lactose (Milk Sugar)β-D-Galactose + β-D-Glucoseβ(1→4)Reducing
Sucrose (Cane Sugar / Invert Sugar)α-D-Glucose + β-D-Fructoseα-1,2-β (1→2)Non-Reducing
Reducing Sugar: Sugars having a free CHO/CO group present, which converts Cu²⁺ to Cu⁺. Test: Fehling's Test, Benedict's Test. All monosaccharides and all disaccharides except sucrose are reducing sugars.
Non-Reducing Sugar: Free CHO/CO group is absent. e.g. Sucrose (Linkage: 1→2, between left end (non-reducing) and right end).

Polysaccharides

Macromolecule, present in acid insoluble pool. Tasteless, insoluble in water. Produced by >10 monosaccharides. Linkage — Glycosidic linkage. Left end — non-reducing.

Storage Polysaccharide

Structural Polysaccharide

Starch

Total Starch is divided into two types:

Type% of Total StarchLinkageStructure
Amylose (Unbranched)20%α(1→4)Each turn of the helix contains 6 units of α-D-glucose. Gives blue colour with I₂ (Iodine).
Amylopectin (Branched)80%Straight chain α(1→4) linkage + α(1→6) linkage at branch points; branching after every 9 unitsBranched structure

Glycogen

Polymer of α-glucose. Branched structure, Linkage: chain α(1→4), branching α(1→6) after every 9 units. Glycogen is found in animals.

Cellulose

Polymer of β-glucose, unbranched structure, Linkage: β(1→4). 1st most abundant polymer, present in cell wall of plant, algae. Used in wood pulp. Cellulose enzyme is absent in animals — animals cannot release/digest cellulose.

Chitin

Polymer of N-acetylglucosamine. Unbranched structure, Linkage: β(1→4). Most abundant polymer present in arthropod exoskeleton, present in fungal cell wall.

Heteropolysaccharide

Amino Acids

Monomer unit of Protein. Micromolecules, present in acid soluble pool.

Structure

A central Carbon (α-Carbon) is attached to: Amino group (NH₂), Carboxyl group (COOH), Alkyl group (R), and a Hydrogen atom.

Property of Amino Acids

Zwitterionic Form of Amino Acid

A particular property of amino acids is the ionizable nature of -NH₂ and -COOH groups. Hence in solutions of different pH, the structure of amino acids changes:

Essential and Non-Essential Amino Acids

Essential Amino Acids: Cannot be created by the body and have to be consumed via diet. Examples: Tryptophan, Phenylalanine, Methionine, Threonine, Histidine, Leucine + 3 more.
Non-Essential Amino Acids: Can be created by the body. Examples: Tyrosine, Proline, Glutamic acid, Cysteine, Arginine, Serine, Asparagine.

Classification of Amino Acids

Derivatives of Amino Acids

Proteins

Proteins are polypeptides — amino acids linked by peptide bonds are linear chains. The protein chain has an N-terminus (NH₂) and a C-terminus (COOH).

Peptide Bond and Bonding Angle of Protein

Peptide bond is a covalent bond. The bonding angle φ (phi) = ±180° and ψ (psi) = ±180°.

Molecular Weight of Protein

Each protein is a polymer of amino acids. As there are 20 types of amino acid, the average molecular weight of an amino acid (after loss of water during peptide bond formation) is taken as 128 (Amino acid = 128 × n — n × 18 for water loss, where n = number of amino acids, AA — H₂O = 110 average residue weight).

Structure of Protein — Four Levels

While organic chemists always write a structural formula for a molecule (e.g. benzene, naphthalene) representing a two-dimensional/three-dimensional view, biologists describe the structure of protein at four levels:

Primary Structure: Linear sequence of amino acids joined by peptide bonds.
Secondary Structure: e.g. α-Helix — right-handed (clockwise), rise of 0.54 nm per turn, number of amino acids per turn = 3.6.
Tertiary Structure: 3-dimensional folding of a protein, e.g. Myoglobin.
Quaternary Structure: More than one polypeptide chain (subunit) associates — e.g. Haemoglobin, Antibody.

Bonds Stabilising Protein Structure

Denaturation of Protein

Denaturation — Breakdown of non-covalent interaction and covalent bonds (disulphide bond) but not the peptide bond, resulting in loss of biological activity (3D structure).

Factors Responsible for Denaturation of Protein

Functions of Proteins (Examples)

ProteinRole
CollagenMost abundant Animal Protein
RUBPCOMost abundant Plant Protein
InsulinHormone — Released from Pancreas
Insulin receptorIntercellular Enzyme/Hormone receptor
AntibodyFights infectious agents
ReceptorSensory reception (e.g. taste)
GLUTIf Blood Glucose level enables uptake of glucose into cells, e.g. muscular cells

Lipids (Fat)

Water insoluble, but soluble in organic solvents. Molecular weight < 800 Dalton. Present in acid insoluble pool, not a polymer. But part of macromolecule pool.

Structure

It is formed by esterification of Glycerol (Glycerol = Propane with 3 -OH groups) with Fatty acids:

CH₂-OH + HOOC-R → CH₂-O-C-R (Ester) + H₂O

Lipid = Glycerol + Fatty acids

Types of Fatty Acids

TypeDouble BondState at Room TempMelting PointMostly present inEffectExamples
SaturatedAbsentSolidHighAnimal FatCause Heart diseasePalmitic acid (C₁₆), Stearic acid (C₁₉H₃₁-COOH form referenced)
UnsaturatedOne or more presentLiquidLowPlantPrevent Heart diseaseOleic acid (1 double bond), Linoleic acid (2), Linolenic acid (3), Arachidonic acid (4)
Essential Fatty Acids: Linoleic acid, Linolenic acid, Arachidonic acid.
Non-Essential Fatty Acids: Palmitic acid, Stearic acid, Oleic acid.

Classification of Lipids

Enzymes

Mostly enzymes are Proteins (Biocatalyst). Globular, with active site/binding sites/crevices. Ribozyme — RNA with tertiary structure and catalytic activity (e.g. RNase P, an endonuclease).

Difference between Biocatalyst and Inorganic Catalyst

Biocatalyst (Enzyme)Inorganic Catalyst
Formed by Protein, present in living bodyFormed by Ions, present in living body
Highly SpecificNon-specific
Highly EfficientLess Efficient
Inactivated at High Temp, except thermophile bacteria (e.g. polymerase)Active at High Temperature

Physical and Chemical Change

Rate of Chemical/Physical Process

Factors which influence the rate: Temperature, pH, substrate concentration, presence of inhibitor.

In the presence of enzyme Carbonic Anhydrase, 600,000 molecules of product are produced per second. (In absence of enzyme, the rate of reaction is much lower — e.g. order of 10⁻⁶ to a much smaller value).

How do Enzymes Bring About Such a High Rate of Conversion?

By reducing the Activation Energy required for the initiation of a chemical reaction.

E + S → ES → EP → E + P

The reaction passes through a Transitional state. Activation energy without enzyme is higher than activation energy in presence of enzyme. The reaction shows a Free Energy Change (ΔG) — exothermic nature, releasing energy. Substrate (e.g. Sucrose) binds at the Active Site of enzyme, forming ES complex, which converts to E + Products (Glucose + Fructose).

Factors Affecting Enzyme Activity

(i) Temperature

Optimum temperature of enzyme = 37°C. Below and above optimum, Vmax decreases (inactivation). A rise of 10°C in temperature increases Vmax (up to optimum, after which it decreases).

(ii) pH

All enzymes are protein (polymer of amino acid). e.g. Salivary Juice (Salivary Amylase) — optimum pH ≈ 6.8; Intestinal Juice — optimum pH ≈ 7.0. Velocity of reaction varies with pH — there is an optimum pH at which Vmax is highest.

(iii) Substrate Concentration

If substrate concentration increases → velocity of reaction increases. But after 100% saturation of enzyme, if substrate concentration increases further, Vmax remains constant. Km = Concentration of substrate at which the reaction rate is half of Vmax.

(iv) Inhibitors

(a) Competitive Inhibition: Vmax remains constant, Km increases. In absence of inhibitor, the enzyme binds normally with substrate. Example: Methanol poisoning — treated using Ethanol, which competes for the same enzyme, preventing toxic formaldehyde formation. Sulpha Drugs (Sulphanilamide) work as competitive inhibitors against PABA (Para amino benzoic acid) used by bacteria in a metabolic pathway. Another example: Succinic acid — Malonate is an inhibitor — Malonate competes with succinic acid for succinic dehydrogenase, blocking conversion to Fumaric acid.
(b) Non-Competitive (Allosteric) Inhibition: Km remains constant, Vmax decreases. This involves binding at a site other than the active site (modulation/change of active site shape) — feedback inhibition. Example: Cytochrome oxidase (ETS) is blocked, which affects the conversion of Glucose → Glucose-6-P (Glu-6-P) pathway; increased Glucose-6-P has an effect on Km of the enzyme.

Classification and Nomenclature of Enzymes

Enzymes are divided into 6 classes, each with 4–13 subclasses. Each enzyme is given a four-digit number (Class.Subclass.Sub-subclass.Individual enzyme number).

ClassFunctionExamples
Oxidoreductases / DehydrogenasesCatalyse oxido-reduction between two substrates. S (reduced) + S' (oxidised) ⇌ S (oxidised) + S' (reduced)—
TransferasesCatalyse transfer of a group, G (other than hydrogen), between a pair of substrates: S–G + S' ⇌ S + S'–GHexokinase, Transaminase
HydrolasesCatalyse hydrolysis of ester, ether, peptide, glycosidic, C-C, C-halide or P-N bondsAll digestive enzymes — Pepsin, Trypsin, Chymotrypsin
LyasesCatalyse removal of groups from substrates by mechanisms other than hydrolysis, leaving double bondse.g. X-Y = C conversion
IsomerasesIncludes all enzymes catalysing inter-conversion of optical, geometric or positional isomerse.g. Carbonic Anhydrase related isomer conversion
LigasesCatalyse the linking together of two compounds, e.g. enzymes which catalyse joining of C-O, C-S, C-N, P-O etc. bondsLigase enzymes

Co-factors

The protein part of the conjugate enzyme present in active form is called the holoenzyme; the protein part without the cofactor is the inactive apoenzyme.

Inorganic Co-factors — Metal Ions: Bind with covalent interaction.
Organic Co-factors:

Dynamic State of Body Constituents — Concept of Metabolism

All living organisms maintain a steady-state concentration of biomolecules — in terms of mol/cell or mol/litre. One of the greatest discoveries ever made was that all these biomolecules are in a turnover, i.e., they are constantly being made and broken down.

Turnover

Turnover number of an enzyme — number of substrate molecules transformed per minute per enzyme molecule. Maximum turnover number → Carbonic Anhydrase.

Flow of metabolites through a metabolic pathway has a definite rate and direction, like automobile traffic. This is called the dynamic state.

Example pathway: Glucose → (Glycolysis) → Pyruvic acid → (Anaerobic respiration, in muscles) → Lactic acid / 2 Alcohol; OR → (Aerobic respiration) → Acetyl Co-A → Krebs cycle.

Anabolic and Catabolic Pathways — Basis for Living

Anabolic Pathway: Formation — consumes energy. Simple → Complex.
Examples: Amino acid → Protein; Simple sugar → Polysaccharide; Nucleotides → Nucleic acid; Acetic acid → Cholesterol.
Catabolic Pathway: Breakdown — releases energy. Complex → Simple.
Examples: Breakdown of glucose, amino acid and fat — leading to formation of ATP.

ATP — Adenosine Triphosphate

The most important form of energy currency in a living system is the bond energy in a chemical called Adenosine Triphosphate (ATP). ATP is composed of: Adenine + Ribose + Triphosphate.

ATP → ADP + Phosphate + Energy released (7.3 kCal/mol)
Steady State: Living systems are not in equilibrium — in equilibrium, work done = 0. Living systems exist in a steady state to be able to perform work, maintaining specific concentrations of metabolites. e.g. Glucose level: 4.2–6.1 mmol/L. Hormone level: 1 nanogram/mL.

Practice Questions

Q1. Which of the following is a non-reducing sugar?

(a) Maltose   (b) Lactose   (c) Sucrose   (d) Glucose

Answer: (c) Sucrose

Explanation: Sucrose is formed by a glycosidic linkage between the anomeric carbons of α-D-glucose (C1) and β-D-fructose (C2). Since both anomeric carbons are involved in the glycosidic bond, no free aldehyde or ketone (CHO/CO) group remains, making sucrose a non-reducing sugar. Maltose, lactose, and glucose all have a free anomeric carbon and hence react with Fehling's/Benedict's reagent.

Q2. Each turn of the helical structure of Amylose contains how many glucose units?

(a) 4   (b) 6   (c) 8   (d) 9

Answer: (b) 6

Explanation: Amylose is the unbranched component of starch with α(1→4) linkages, forming a helical structure. Each complete turn of this helix contains 6 units of α-D-glucose, and this helical arrangement is responsible for the blue colour produced when starch reacts with iodine (I₂).

Q3. Which level of protein structure refers to the linear sequence of amino acids joined by peptide bonds?

(a) Primary structure   (b) Secondary structure   (c) Tertiary structure   (d) Quaternary structure

Answer: (a) Primary structure

Explanation: The primary structure of a protein is simply the linear sequence of amino acids connected through covalent peptide bonds — like beads on a string. Secondary structure refers to local folding patterns (such as the α-helix), tertiary structure is the overall 3D folding (e.g., myoglobin), and quaternary structure involves the association of more than one polypeptide chain (e.g., haemoglobin).

Q4. Malonate inhibits succinic dehydrogenase by which mechanism?

(a) Non-competitive inhibition   (b) Competitive inhibition   (c) Irreversible inhibition   (d) Feedback inhibition only

Answer: (b) Competitive inhibition

Explanation: Malonate has a structure similar to succinic acid, the natural substrate of succinic dehydrogenase, and therefore competes with it for the enzyme's active site. In competitive inhibition, Vmax remains unchanged but Km increases, since more substrate is needed to overcome the competition from the inhibitor and reach the same reaction velocity.

Q5. Cholesterol, classified under derived lipids, is composed of which type of ring structure?

(a) Only a hexagonal ring   (b) Penta + Hexa fused ring system with hydrocarbon chain   (c) A polymer of glucose units   (d) Ester of glycerol and three fatty acids only

Answer: (b) Penta + Hexa fused ring system with hydrocarbon chain

Explanation: Cholesterol belongs to the derived lipids and has a steroid nucleus consisting of fused hexagonal (hexa) rings along with one pentagonal (penta) ring, attached to a hydrocarbon side chain. Unlike triglycerides, cholesterol does not contain fatty acids in ester linkage, and it acts as the precursor for steroid hormones produced by the adrenal cortex and gonads.

Q6. The energy released on hydrolysis of ATP to ADP and phosphate is approximately:

(a) 1 kCal/mol   (b) 3.5 kCal/mol   (c) 7.3 kCal/mol   (d) 15 kCal/mol

Answer: (c) 7.3 kCal/mol

Explanation: ATP (Adenosine Triphosphate) is composed of adenine, ribose sugar and three phosphate groups linked by high-energy phosphoanhydride bonds. Hydrolysis of the terminal phosphate bond (ATP → ADP + Pi) releases approximately 7.3 kCal/mol of energy, which living systems use to perform various forms of work, helping maintain the steady state described in the dynamic state of body constituents.

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