← Home
Physics · Complete Chapter

EMI & Alternating Current

Faraday's Law · Lenz's Law · Motional EMF · Self Inductance · Mutual Inductance · AC Circuits · LCR Resonance · Transformer

Faraday's LawLenz's LawMotional EMF Self InductanceMutual InductanceEddy Currents AC CircuitsLCR ResonanceTransformer
Advertisement
1

Magnetic Flux and Faraday's Law

Magnetic Flux
Faraday's Law: EMF = −dΦ/dt   (induced EMF = rate of change of flux)
Average EMF = −ΔΦ/Δt   |   Induced current I = EMF/R = −(1/R) × dΦ/dt
Based on Conservation of Energy
Lenz's Law
2

Motional EMF

EMF for rod of length L moving with velocity v in field B: EMF = BLv sinθ
For v ⊥ B ⊥ L: EMF = BLv (maximum)
Induced current: I = BLv/R
Force on rod: F = BIL = B²L²v/R (opposing motion)
Power dissipated: P = F·v = B²L²v²/R
Rotating Rod/Disc in Magnetic Field

Rod rotating about one end: EMF = ½BωL²   (L = length of rod)

Rotating disc (radius R): EMF = ½BωR²   (disc = collection of infinite rods)

Rotating coil (N turns, area A, angular freq ω):

Φ = NBA cos(ωt); EMF = NBAω sin(ωt) = E₀ sin(ωt)

E₀ = NBAω (maximum EMF = peak EMF)

3

Self Inductance

Definition
Self inductance of solenoid: L = μ₀n²Al = μ₀N²A/l
With iron core: L = μ₀μrn²Al
Energy stored in inductor: U = ½LI²
Magnetic energy density: u = B²/(2μ₀)
Series inductors: Leq = L₁ + L₂ (no mutual inductance)
Parallel inductors: 1/Leq = 1/L₁ + 1/L₂
Growth and Decay of Current in Inductor (L-R Circuit)
Advertisement
4

Mutual Inductance and Eddy Currents

Φ₁₂ = MI₂ (flux in coil 1 due to current I₂ in coil 2); similarly Φ₂₁ = MI₁
EMF₁ = −M × dI₂/dt; M depends only on geometry, NOT on current or flux
Reciprocity theorem: M₁₂ = M₂₁ (always true)
For two coils: M = K√(L₁L₂) where K = coupling factor (0 ≤ K ≤ 1)
Series (same flux direction): Leq = L₁ + L₂ + 2M
Series (opposite flux direction): Leq = L₁ + L₂ − 2M
Eddy Currents
5

Alternating Current — Basics

AC vs DC
Waveform<I> Full cycle<I> Half cycleIrms
Sinusoidal: I₀ sin(ωt)02I₀/πI₀/√2
Square wave (±I₀)0I₀I₀
Triangular wave (±I₀)0I₀/2I₀/√3
DC = a, AC = b sin(ωt)a—√(a² + b²/2)
Full wave rectified2I₀/π2I₀/πI₀/√2
Half wave rectifiedI₀/πI₀/2I₀/2
Key Values for Sinusoidal AC
6

AC Circuits — Pure R, L, C

CircuitPhase relationReactancePower <P>At f=0 (DC)At f=∞
Pure ResistorV and I in phase (φ = 0)R (constant)IrmsVrmsActs as RActs as R
Pure InductorV leads I by 90° (φ = +90°)XL = ωL = 2πfL0 (wattless)XL=0, simple wireXL=∞, open wire
Pure CapacitorI leads V by 90° (φ = −90°)XC = 1/(ωC) = 1/(2πfC)0 (wattless)XC=∞, open wireXC=0, simple wire
7

Series LCR Circuit and Resonance

Impedance: Z = √(R² + (XL − XC)²)
Phase angle: tan φ = (XL − XC)/R
Power factor: cos φ = R/Z
Average power: <P> = IrmsVrms cos φ = I²rmsR
Resonance: XL = XC → ω₀ = 1/√(LC) → f₀ = 1/(2π√LC)
At resonance: Z = R (minimum); I = maximum; cos φ = 1; <P> = maximum
Three Cases in LCR Series Circuit
  • XL > XC: Inductive dominance; voltage leads current; φ > 0
  • XL = XC: Resonance; Z = R (minimum); I = maximum; cos φ = 1
  • XL < XC: Capacitive dominance; current leads voltage; φ < 0

At resonance: VL = VC (may individually be greater than source V!)

Quality Factor and Bandwidth
⚡ Choke Coil
Advertisement
8

LC Oscillations

Energy Exchange in LC Circuit
Angular frequency: ω = 1/√(LC)
Time period: T = 2π√(LC)
Analogy: L ↔ mass m; C ↔ 1/k (spring); q ↔ x; I ↔ v
9

Transformer

Principle and Working
Vs/Vp = Ns/Np = Ip/Is
Power: Pin = VpIp = VsIs = Pout (ideal)
Efficiency: η = Pout/Pin = 1 (100%) for ideal; <1 for practical
TypeConditionVoltageCurrent
Step-Up transformerNs > NpVout > VinIout < Iin
Step-Down transformerNs < NpVout < VinIout > Iin
Power Losses in Transformer
Q: A rod of length 1 m moves with v = 5 m/s ⊥ to B = 0.2 T. Resistance of circuit = 2 Ω. Find induced EMF, current and force on rod.
EMF = BLv = 0.2×1×5 = 1 V; I = EMF/R = 1/2 = 0.5 A; F = BIL = 0.2×0.5×1 = 0.1 N (opposing motion)
Ans: EMF = 1 V; I = 0.5 A; F = 0.1 N ✓
Q: Series LCR circuit: R = 10 Ω, L = 0.1 H, C = 100 μF. Find resonance frequency and Q factor.
f₀ = 1/(2π√LC) = 1/(2π√(0.1×10⁻⁴)) = 1/(2π×10⁻²·⁵) ≈ 50.3 Hz; Q = ω₀L/R = (2π×50.3×0.1)/10 ≈ 0.316
Ans: f₀ ≈ 50.3 Hz; Q ≈ 0.316 ✓
Q: Transformer: 220 V input, 11 V output, input current 0.5 A. Find turns ratio and output current (ideal).
Np/Ns = Vp/Vs = 220/11 = 20; Is = IpVp/Vs = 0.5×220/11 = 10 A
Ans: Turns ratio = 20:1; Iout = 10 A ✓
Advertisement
📥 Download Complete PDF

Complete chapter notes — all topics — free download

⬇ DOWNLOAD PDF — FREE
Save as PDF from this page:
  1. Press Ctrl+P (Windows) / Cmd+P (Mac)
  2. Select "Save as PDF"
  3. Click Save
Advertisement
Advertisement