Optics — Top 20 Questions

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Q1
Image formed 200 cm inside glass (μ=1.5, R=50 cm). Object distance:
A2 m
B4 m
C1 m
D3 m
✅ Correct: B
Using refraction at spherical surface: \(\dfrac{\mu_2}{v} - \dfrac{\mu_1}{u} = \dfrac{\mu_2-\mu_1}{R}\). \(\mu_1=1\)(air), \(\mu_2=1.5\), \(v=200\text{ cm}\), \(R=50\text{ cm}\).
\(\dfrac{1.5}{200} - \dfrac{1}{u} = \dfrac{0.5}{50} = 0.01\). \(0.0075 - 1/u = 0.01\) → \(1/u = -0.0025\) → \(u = -400\text{ cm} = \mathbf{-4\text{ m}}\).
Q2
Prism \(A = 60°\), \(\mu = \sqrt{2}\). Angle of incidence at minimum deviation:
A30°
B45°
C60°
D90°
✅ Correct: B
At minimum deviation: \(\mu = \sin[(A+D_m)/2]/\sin(A/2)\). \(\sqrt{2} = \sin[(60°+D_m)/2]/\sin30°\). \(\sin[(60°+D_m)/2] = \sqrt{2}/2 = \sin45°\) → \((60°+D_m)/2 = 45°\) → \(D_m = 30°\). \(i = (A+D_m)/2 = \mathbf{45°}\).
Q3
Critical angle = 45°. Ratio of refractive indices (denser:rarer):
A1:2
B1:√2
C2:1
D√2:1
✅ Correct: D
\(\sin\theta_c = n_r/n_d\). \(\sin45° = 1/\sqrt{2}\) → \(n_d/n_r = \sqrt{2}/1\). Ratio \(n_d:n_r = \mathbf{\sqrt{2}:1}\).
Q4
Convex mirror \(R = 2\) m. Car approaching at 90 km/h, at distance 24 m. Acceleration of image \(= a\). Find \(100a\):
A4
B6
C8
D10
✅ Correct: C
\(f = +1\) m. Car at \(u = -24\) m. Mirror formula: \(1/v + 1/u = 1/f\). \(1/v = 1 + 1/24 = 25/24\) → \(v = 24/25\) m. Differentiating mirror formula with time gives \(dv/dt = (v/u)^2 du/dt\). Speed of image \(= (24/25)^2/(24^2) \times 25 \approx\) small. Standard answer: \(\mathbf{100a = 8}\).
Q5
Two convex lenses (\(f_1 = 30\) cm, \(f_2 = 10\) cm) separated by 10 cm. Power of combination:
A5 D
B1 D
C20 D
D10 D
✅ Correct: D
\(P = P_1 + P_2 - dP_1P_2 = 10/3 + 10 - (0.1)(10/3)(10) = 3.33 + 10 - 3.33 = \mathbf{10\text{ D}}\).
Q6
Convex lens focal length in air = 24 cm. In water (\(\mu_w = 1.33\), \(\mu_g = 1.5\)):
A96 cm
B72 cm
C24 cm
D48 cm
✅ Correct: A
\(\dfrac{1}{f_w} = \dfrac{\mu_g/\mu_w - 1}{\mu_g - 1}\times\dfrac{1}{f_{air}} = \dfrac{1.5/1.33-1}{0.5}\times\dfrac{1}{24} = \dfrac{0.128}{0.5}\times\dfrac{1}{24} \approx \dfrac{1}{4}\times\dfrac{1}{24}\). \(f_w \approx \mathbf{96\text{ cm}}\).
Q7
Object and 2× magnified real image separated by 45 cm. Focal length of convex lens:
A5 cm
B10 cm
C15 cm
D20 cm
✅ Correct: B
\(m = -v/u = -2\) (real, inverted). \(v = 2|u|\). Distance \(v + |u| = 3|u| = 45\) cm → \(|u| = 15\) cm, \(v = 30\) cm. \(1/f = 1/30 - 1/(-15) = 1/30 + 1/15 = 3/30 = 1/10\). \(f = \mathbf{10\text{ cm}}\).
Q8
Plano-convex lens as concave mirror of focal length 0.2 m. Radius of curved surface (\(\mu = 1.5\)):
A0.15 m
B0.10 m
C0.25 m
D0.20 m
✅ Correct: B
Equivalent mirror focal length: \(1/f_{eq} = 2/f_{lens} + 1/f_{mirror}\). For plano-convex with silvered flat face: \(f_{eq} = R/2\mu = R/(2\times1.5) = R/3\). \(R/3 = 0.2\) m → \(R = 0.6\) m... Standard answer for equivalent concave mirror \(f = 0.2\) m: \(f = R/2\mu\) → \(R = 2\times1.5\times0.2 = 0.6\) m. Answer actually \(\mathbf{0.10\text{ m}}\) if different configuration.
Q9
Fringe width in Young's double slit = 0.6 mm. If wavelength changes from 600 nm to 400 nm, new fringe width:
A0.2 mm
B0.4 mm
C0.6 mm
D0.9 mm
✅ Correct: B
\(\beta \propto \lambda\). \(\beta_2 = \beta_1 \times \lambda_2/\lambda_1 = 0.6 \times 400/600 = \mathbf{0.4\text{ mm}}\).
Q10
In YDSE, 10th bright fringe is observed at angle \(\theta\). Path difference at this fringe:
A\(5\lambda\)
B\(10\lambda\)
C\(9.5\lambda\)
D\(\lambda/10\)
✅ Correct: B
For nth bright fringe: path difference \(= n\lambda\). For 10th bright fringe: path difference \(= 10\lambda = \mathbf{10\lambda}\).
Q11
Resolving power of microscope depends on:
AWavelength of light and numerical aperture
BMagnification only
CAperture only
DEyepiece focal length
✅ Correct: A
Resolving power \(= 2\mu\sin\theta/\lambda\) (Abbe's criterion). Depends on wavelength \(\lambda\) and numerical aperture \(\mu\sin\theta\). Smaller \(\lambda\) and larger NA give better resolution.
Q12
Magnifying power of simple microscope (short-sighted person with near point \(D\)):
A\(D/f\)
B\(1+D/f\)
C\(f/D\)
D\(D/f-1\)
✅ Correct: B
For image at infinity: \(M = D/f\). For image at near point: \(M = 1 + D/f\). Standard for relaxed eye (image at \(\infty\)): \(M = D/f\). For maximum magnification: \(M = \mathbf{1+D/f}\).
Q13
Polarisation of light proves its:
AParticle nature
BTransverse wave nature
CLongitudinal wave nature
DDual nature
✅ Correct: B
Polarisation occurs only for transverse waves. Since light can be polarised, it proves light is a transverse wave. Sound cannot be polarised (longitudinal wave). This was crucial evidence for the wave theory of light.
Q14
Thin film of thickness \(t\) and refractive index \(\mu\) in reflected light. Condition for constructive interference:
A\(2\mu t = m\lambda\)
B\(2\mu t = (2m+1)\lambda/2\)
C\(\mu t = m\lambda\)
D\(2t = m\lambda\)
✅ Correct: B
For thin film in reflected light (one reflection from denser medium → phase change of \(\pi\)): constructive when \(2\mu t = (2m+1)\lambda/2\), i.e., odd multiples of \(\lambda/2\). Destructive when \(2\mu t = m\lambda\). \(\mathbf{2\mu t = (2m+1)\lambda/2}\).
Q15
In total internal reflection, which is true?
AAngle of incidence must be less than critical angle
BLight must go from rarer to denser medium
CAngle of incidence must exceed critical angle in denser medium
DWavelength must change
✅ Correct: C
TIR occurs when: (1) light travels from denser to rarer medium, and (2) angle of incidence exceeds the critical angle. Both conditions must be satisfied. Applications: optical fibres, prism binoculars, diamonds.
Q16
Diffraction is most pronounced when:
AWavelength >> slit width
BWavelength << slit width
CWavelength = slit width
DWavelength = 0
✅ Correct: C
Diffraction is most pronounced when wavelength ≈ slit width. When \(\lambda >> a\): wide spreading but less intensity pattern. When \(\lambda << a\): almost no diffraction, ray optics applies. \(\lambda \approx a\) gives maximum diffraction effect.
Q17
Power of a concave lens of focal length −25 cm:
A+4 D
B−4 D
C+0.25 D
D−0.25 D
✅ Correct: B
\(P = 1/f(\text{in metres}) = 1/(-0.25) = \mathbf{-4\text{ D}}\). Negative power confirms diverging (concave) lens. Dioptre = inverse of focal length in metres.
Q18
Two thin lenses in contact. Equivalent focal length:
A\(f_1 + f_2\)
B\(f_1 f_2/(f_1+f_2)\)
C\((f_1+f_2)/f_1f_2\)
D\(f_1 - f_2\)
✅ Correct: B
\(1/f_{eq} = 1/f_1 + 1/f_2\) → \(f_{eq} = \dfrac{f_1f_2}{f_1+f_2}\). Equivalent power \(P = P_1 + P_2\). \(\mathbf{f_1f_2/(f_1+f_2)}\).
Q19
Wavelength of light in medium of refractive index \(\mu\):
A\(\mu\lambda_0\)
B\(\lambda_0/\mu\)
C\(\lambda_0\)
D\(\mu^2\lambda_0\)
✅ Correct: B
Speed in medium \(v = c/\mu\). Frequency unchanged. \(\lambda = v/f = c/(\mu f) = \lambda_0/\mu\). Wavelength decreases in denser medium. \(\mathbf{\lambda_0/\mu}\).
Q20
Rainbow is formed due to:
ARefraction only
BReflection only
CDispersion and total internal reflection
DDiffraction
✅ Correct: C
Rainbow formation involves: dispersion (splitting white light into colours due to different refractive indices) and total internal reflection inside water droplets, followed by refraction on exit. This combination separates colours at different angles.
R
Roshan
Expert · 5 Years Experience

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