DEFINITION
Minimum required energy to remove most loosely bounded eβ» from gaseous isolated atom.
Note: Always Endothermic for Neutral & Cations.
Q: In which of the following the energy change corresponds to first ionisation potential?
β
Ans: (a) \(X_2(g) \rightarrow X^+(g) + e^-\)
Value of Successive Ionisation Energy
\[ M(g) \xrightarrow{IE_1} M^+(g) \xrightarrow{IE_2} M^{2+}(g) \xrightarrow{IE_3} M^{3+}(g) \]
\[ IE_3 > IE_2 > IE_1 \]
Factors Affecting Ionisation Energy
β Size
\[ IE \propto \frac{1}{\text{Size}} \]
β‘ Z_eff
\[ IE \propto \frac{Z_{eff}}{\sigma} \]
β’ Stable Configuration
- Fully filled (Inert gas config) β Extra stability β Higher IE
- Half filled β Extra stability β Higher IE
- Max ionisation energy in a period β Inert gas
β£ Penetration Power
\[ s > p > d > f \]
e.g. Be > B (2sΒ² vs 2pΒΉ); Mg > Al (3sΒ² vs 3pΒΉ)
I.E. of 2nd Period
Li < Be > B < C < N > O < F < Ne
(2sΒΉ) (2sΒ²) (2pΒΉ) (2pΒ²) (2pΒ³) (2pβ΄) (2pβ΅) (2pβΆ)
Final Order (2nd Period)
Li < B < Be < C < O < N < F < Ne
I.E. of 3rd Period
Na < Mg > Al < Si < P > S < Cl < Ar
(3sΒΉ) (3sΒ²) (3pΒΉ) (3pΒ²) (3pΒ³) (3pβ΄) (3pβ΅) (3pβΆ)
Final Order (3rd Period)
Na < Al < Mg < Si < S < P < Cl < Ar
MDJ
If value of n is same, Ionisation Energy order:
\(ns^1 < np^1 < ns^2 < np^2 < np^4 < np^3 < np^5 < np^6\)
IE Order of 2nd I.E.
How to write 2nd I.E.
IEβ = removal of 2nd eβ» (means 1st has already been removed β reduce 1eβ» from configuration)
Order of 2nd I.E. of C, N, O & F
After removing 1 eβ»: C(2pΒΉ), N(2pΒ²), O(2pΒ³), F(2pβ΄)
Order: 2pΒΉ < 2pΒ² < 2pβ΄ < 2pΒ³
C < N < F < O
Order of 2nd I.E. of Na, Mg, Al & Si
After removing 1 eβ»: Na(2pβΆ), Mg(3sΒΉ), Al(3sΒ²), Si(3pΒΉ)
Order: 3sΒ² < 3pΒΉ < 3sΒ² < 2pβΆ
Mg < Si < Al < Na
Block-wise Ionisation Energy
S-Block β No Exception
- Moving Left β Right: I.E. β
- Moving Down the group: I.E. β
- IEβ: AM < AEM (nsΒΉ vs nsΒ²)
- But IEβ: AM > AEM (after removing 1eβ»: nsβ°/npβΆ vs nsΒΉ)
P-Block IE (Top to Bottom)
- Group 15th, 16th, 17th, 18th: IE increases top to bottom (No exception)
- Group 13th: B > Tl > Ga > Al > In (Final order)
- Group 14th: C > Si > Ge > Pb > Sn (Final order)
D-Block IE (Top to Bottom)
- Group 3: 3d < 4d < 5d (No Lanthanoid Contraction)
- Group 4β6, 10: 3d > 4d < 5d (Lanthanoid Contraction)
- Group 7β9, 11, 12: 4d < 3d < 5d
- Note: IE of 5d series element in each group (except 3rd) is maximum due to Lanthanoid Contraction
3d series (Left to Right): Sc < V < Co < Ti < Mn < Ni < Cu < Co < Fe < Zn
Important d-Block Comparisons
| Elements | IEβ | IEβ | Reason |
| Cr vs Mn | Cr < Mn (4sΒΉ vs 4sΒ²) | Cr > Mn (3dβ΅ stable) | Half-filled 3d |
| Cu vs Zn | Cu < Zn (4sΒΉ vs 4sΒ²) | Cu > Zn (3dΒΉβ° stable) | Fully filled 3d |
Applications of I.E.
β Metallic Character / Electropositive Character
When I.E. β β eβ» removal becomes easy β Metallic Character β β Reactivity β
β‘ No. of Valence eβ» & Possible Oxidation States
Large jump between two successive IE values indicates the number of valence electrons.
EXAMPLE
Element X: IEβ(6eV), IEβ(8.5eV), IEβ(122eV), IEβ(119eV)
- No. of valence eβ»: 2
- Possible O.S.: +2
- Formula of OΒ²β»: XΒ²βΊ + OΒ²β» β XO
- Formula of NΒ³β»: XΒ²βΊ + NΒ³β» β XβNβ
- Element X is most likely to be: Mg
β’ Stability of Lower O.S. & Higher O.S.
Rule 1 (Only for s-block): If ΞI.E. β€ 11eV β Higher O.S. will be more stable (MΒ²βΊ > MβΊ)
Rule 2 (For Alkali Metal): If ΞI.E. β₯ 16eV β Lower O.S. will be more stable (MβΊ > MΒ²βΊ)
MDJ β IE of Ion
I.E. of ion β +ve charge / βve charge
Q: Write correct order of I.E. for O, OβΊ, OΒ²βΊ
O < OβΊ < OΒ²βΊ
Q: Write correct order of I.E. for IβΊ, I, Iβ»
IβΊ > I > Iβ»
Q: NΒ³β», OΒ²β», Fβ», NaβΊ, MgΒ²βΊ β Write correct I.E. order
NΒ³β» < OΒ²β» < Fβ» < NaβΊ < MgΒ²βΊ
Q: Which of the following has 2nd IP < 1st IP?
β
Ans: (d) None β 2nd IE is always greater than 1st IE
Q: If the graph is b/w atomic no. & Ionisation potential, which group of elements occupy lowest position on curve?
β
Ans: (d) Alkali Metals
F-Block IE
- Irregular Variations
- IEβ & IEβ of Lanthanoids are similar to Ca
- IEβ of Lanthanoids are similar to Al