Step 1: Assume 100 g of the compound

C = 14.5 g, H = 1.8 g, Cl = 64.46 g

Step 2: Calculate moles of each element

Moles of C = 14.5 / 12 = 1.21
Moles of H = 1.8 / 1 = 1.8
Moles of Cl = 64.46 / 35.5 = 1.82

Step 3: Find simplest mole ratio

Divide by smallest value (≈ 1.21)

C : H : Cl ≈ 1 : 1.49 : 1.5

Step 4: Convert into whole numbers

Multiply by 2:
C : H : Cl = 2 : 3 : 3

Step 5: Write empirical formula

Empirical formula = C₂H₃Cl₃

Step 6: Calculate empirical formula mass

= (2 × 12) + (3 × 1) + (3 × 35.5)
= 24 + 3 + 106.5
= 133.5 g mol⁻¹

Step 7: Express in required format

Empirical formula mass = 1335 × 10⁻¹