Bond Angle Order in BF3, PF3 and ClF3 | JEE Main Chemical Bonding

Increasing Order of Bond Angles in BF₃, PF₃ and ClF₃

Question:
The correct increasing order for bond angles among BF3, PF3 and ClF3 is:

(A) BF₃ = PF₃ < ClF₃
(B) BF₃ < PF₃ < ClF₃
(C) ClF₃ < PF₃ < BF₃
(D) PF₃ < BF₃ < ClF₃

Correct Answer: ClF₃ < PF₃ < BF₃

Explanation (VSEPR Theory)

According to VSEPR theory, bond angle depends on molecular geometry and the number of lone pairs on the central atom.

BF₃:
Trigonal planar geometry with no lone pairs. Bond angle ≈ 120° (maximum).

PF₃:
Trigonal pyramidal geometry with one lone pair. Lone pair–bond pair repulsion reduces bond angle (< 109.5°).

ClF₃:
T-shaped geometry with two lone pairs on chlorine. Strong lone pair–lone pair repulsion causes minimum bond angle.

Hence, the increasing order of bond angles is:

ClF₃ < PF₃ < BF₃

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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