Options:
1. 20
2. 6
3. 10
4. 120
Correct Answer: 10
Step 1:
If a polynomial is divisible by x² + 2, then x = √2 i and x = −√2 i must be its roots.
Step 2:
Substitute x = √2 i in x³ + ax² + bx + c = 0
⇒ −2√2 i − 2a + b√2 i + c = 0
Step 3:
Equating real and imaginary parts:
Step 4:
Since c ≤ 20 ⇒ 2a ≤ 20 ⇒ a ≤ 10 So, a can take 10 values.
Hence, total number of polynomials = 10
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.