Correct Answer: 30
Loss of gravitational potential energy of the falling mass is:
mgh = 3 × 10 × 3 = 90 J
This energy is converted into translational kinetic energy of the mass and rotational kinetic energy of the flywheel.
Moment of inertia of the flywheel (solid disc) is:
I = ½ MR2 = ½ × 3 × 25 = 37.5 kg m2
Using equations of motion for a mass–pulley system:
a = mg / (m + I/R2)
a = 30 / (3 + 37.5/25) = 30 / 4.5 = 6.67 m/s2
Velocity of the mass after descending 3 m:
v2 = 2as = 2 × 6.67 × 3 = 40
Translational kinetic energy of the mass:
K = ½ mv2 = ½ × 3 × 40 = 60 J
Hence, rotational kinetic energy of the flywheel is:
90 − 60 = 30 J
Therefore, the kinetic energy of the wheel is 30 J.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.