The correct order of acidic strength of the major products formed in the given reactions, is

Q. The correct order of acidic strength of the major products formed in the given reactions, is :

A. PhNH2 → (1) NaNO2 + HCl (< 5°C) → (2) CuCN → (3) H3O+ / Δ → [A]

B. CH3CH2CHO → [Ag(NH3)2]+, OH, Δ → [B]

C. CH4 + O2 → (i) Mo2O3 → (ii) Na2Cr2O7 / H+ → [C]

D. PhCH2MgBr + CO2 → Dry ether → H3O+ → [D]

Choose the correct answer from the options given below :

A. C > A > D > B
B. A > D > C > B
C. A > D > B > C
D. C > B > A > D

Correct Answer: C > A > D > B

Explanation

First, identify the major products formed in each reaction.


Reaction A

Aniline (PhNH2) undergoes diazotisation with NaNO2/HCl at low temperature to form benzene diazonium chloride.

On treatment with CuCN (Sandmeyer reaction), it forms benzonitrile (PhCN).

Acidic hydrolysis of nitrile gives benzoic acid (C6H5COOH).

So, product [A] = Benzoic acid.


Reaction B

CH3CH2CHO (propanal) with Tollens’ reagent is oxidised to propanoic acid (CH3CH2COOH).

So, product [B] = Propanoic acid.


Reaction C

Controlled oxidation of methane using Mo2O3 followed by strong oxidation with Na2Cr2O7/H+ gives carbonic acid (H2CO3).

So, product [C] = Carbonic acid.


Reaction D

Grignard reagent PhCH2MgBr reacts with CO2 followed by acidic workup to give phenylacetic acid (C6H5CH2COOH).

So, product [D] = Phenylacetic acid.


Now compare acidic strength:

Carbonic acid is strongest due to inorganic nature and high polarity.

Benzoic acid is stronger than phenylacetic acid due to resonance stabilisation of its conjugate base.

Propanoic acid is the weakest among these.

Therefore, the correct order is:

C > A > D > B

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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