E(x, t) = 25 sin (2.0 × 1015 t − 107 x) n̂
then the refractive index of the medium is ______.
(All given measurement are in SI units)
(A) 2
(B) 1.2
(C) 1.5
(D) 1.7
Correct Answer: 1.5
The standard equation of an electromagnetic wave is:
E(x, t) = E0 sin (ωt − kx)
Comparing it with the given equation:
ω = 2.0 × 1015 rad s−1
k = 107 m−1
The speed of the electromagnetic wave in the medium is:
v = ω / k
v = (2.0 × 1015) / (107) = 2.0 × 108 m s−1
Refractive index of the medium is given by:
n = c / v
n = (3.0 × 108) / (2.0 × 108) = 1.5
Hence, the refractive index of the medium is:
1.5
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.