(A) 3.3
(B) 27
(C) 2.7
(D) 5.4
Correct Answer: 2.7
Work done in bringing a charge from infinity is equal to the electric potential at that point multiplied by the charge.
V = k (q1/r + q2/r)
Here,
q1 = 1 nC, q2 = 2 nC, r = 3 cm = 0.03 m
V = 9×109 × (3×10−9 / 0.03) = 900 V
Work done:
W = qV = 3×10−9 × 900 = 2.7×10−6 J
W = 2.7 μJ
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.