Correct Answer: 2
In simple harmonic motion, the potential energy of the particle is given by:
U = ½ kx²
The potential energy is maximum when the displacement x is maximum.
Given:
x(t) = A sin ωt
Maximum displacement occurs when:
sin ωt = ±1
This happens at:
ωt = π / 2
Using ω = 2π / T:
(2π / T) t = π / 2
t = T / 4
Comparing with:
t = T / 2β
T / 2β = T / 4
β = 2
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.