Q. Let A, B and C be three 2 × 2 matrices with real entries such that
B = (I + A)−1 and A + C = I.
If
BC =
[
1−5
−12
]
and
CB
[
x1
x2
]
=
[
12
−6
]
,
then x1 + x2 is
Explanation
B = (I + A)−1 and A + C = I
From A + C = I, we get
C = I − A
Now,
CB = (I − A)B = B − AB
Since,
(I + A)B = I
⇒ AB = I − B
Substitute:
CB = B − (I − B) = 2B − I
Thus CB is fully known.
Solving CB
[
x1
x2
]
=
[
12
−6
]
gives
x1 + x2 = 0