In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers is ____ mm.

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers is

Q. In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division = 0.05 mm, then the least count of the vernier callipers is ____ mm.

(A) 0.002

(B) 0.02

(C) 0.05

(D) 0.005

Correct Answer: 0.002 mm

Explanation

It is given that 50 vernier scale divisions are equal to 48 main scale divisions.

Therefore,

1 vernier scale division = ⁴⁸/₅₀ main scale divisions

= ²⁴/₂₅ main scale division

One main scale division = 0.05 mm

So,

1 vernier scale division = ²⁴/₂₅ × 0.05 mm

= 0.048 mm

Least count of vernier callipers is defined as the difference between one main scale division and one vernier scale division.

Least count = 1 MSD − 1 VSD

= 0.05 − 0.048

= 0.002 mm

Hence, the least count of the vernier callipers is 0.002 mm.

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