Combustion of glucose (C₆H₁₂O₆) produces CO₂ and water.The amount of oxygen (in g) required for the complete combustion of 900 g of glucose is :

Combustion of Glucose Oxygen Requirement | JEE Mains Previous Year Question

Q. Combustion of glucose (C₆H₁₂O₆) produces CO₂ and water. The amount of oxygen (in g) required for the complete combustion of 900 g of glucose is : [ Molar mass of glucose in g mol⁻¹ = 180 ]

Step 1: Write the balanced chemical equation

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

Step 2: Calculate number of moles of glucose

Moles of glucose = 900 / 180 = 5 mol

Step 3: Use mole ratio from balanced equation

1 mole of glucose requires 6 moles of oxygen Therefore, 5 moles of glucose require = 5 × 6 = 30 moles of oxygen

Step 4: Convert moles of oxygen into mass

Molar mass of O₂ = 32 g mol⁻¹ Mass of oxygen required = 30 × 32 = 960 g

Final Answer: 960 g

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