(A) NAhc / 250(y − 6x)
(B) NAhc (y − 6x/4)−1
(C) (hc / 1000) ( (y − 6x) / 4 )−1
(D) NAhc / 250(4y − 6x)
Correct Answer: NAhc / 250(4y − 6x)
Heat of atomisation of methane:
CH₄ → C + 4H x = 4 × (C–H)
So,
C–H bond energy = x / 4
Heat of atomisation of ethane:
C₂H₆ → 2C + 6H y = 6(C–H) + (C–C)
Substitute C–H value:
y = 6(x/4) + (C–C) C–C = y − 3x/2 = (4y − 6x)/4
Energy per bond in joule:
E = (4y − 6x) × 10³ / (4NA)
Longest wavelength required:
λ = hc / E
On substitution:
λ = NAhc / 250(4y − 6x)
Hence, the correct answer is option (D).
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.